All categories

2 years ago

-2x^2+bx -5 Determine the b-value that would ensure the function has two real root.

Mathematics

1 answer:

anastassius [24]2 years ago

8 0

Answer:

No solution

Step-by-step explanation:

Given is the quadratic function

y = -2x² + bx - 5

In order to have two real roots the discriminant should be posivive

D = - b² - 4ac
D = - b² - 4(-2)(-5) = - b² - 40

We need D > 0

-b² - 40 > 0
b² + 40 < 0
b² < - 40

There is no solution as b² is never negative

You might be interested in

Urgent!! Math help!!

iragen [17]

Answer:

Step-by-step explanation:

20^2+21^2=841

5 0

3 years ago

How do I solve this?

Crazy boy [7]

Answer:

71°

142°

Step-by-step explanation:

$\because QS \: is \: the \: bisector \: of \: \angle \: PQR\\\therefore m\angle RQS =m\angle PQS\\\because m\angle RQS = 71\degree...(given) \\ \huge \red{ \boxed{\therefore m\angle PQS = 71\degree}} \\ \because \: m\angle \: PQR = m\angle PQS + m\angle RQS \\ \because \: m\angle \: PQR = 71\degree + 71\degree \\ \huge \purple{ \boxed{\therefore \: m\angle \: PQR = 142\degree}}$

7 0

3 years ago

(⅔)-⁴ (two over three to the power minus 4)<br><br>I need answer asap pleaseeeee

Fudgin [204]

Answer:

81/16

Step-by-step explanation:

(⅔)-⁴

81/16

= 5.0625

8 0

3 years ago

Find the range of p in equation p(x+1) (x-3)=x-4p-2 has no real roots.

Tanya [424]

Answer:

$\displaystyle p > \frac{1}{4}$ .

Step-by-step explanation:

Expand the left-hand side of this equation:

$p\, (x + 1)\, (x - 3) = p\, \left(x^2 - 2\, x - 3\right) = p\, x^2 - 2\, p\, x - 3\, p$ .

Collect the terms, so that this quadratic equation is in the form $a\, x^2 + b\, x+ c = 0$ :

$p\, x^2 - 2\, p\, x - 3\, p = x - 4\, p - 2$ .

$p\, x^2 - (2\, p + 1)\, x + (p + 2) = 0$ .

In this equation:

$a = p$ .
$b = -(2\, p + 1)$ .
$c = p + 2$ .

Calculate the quadratic discriminant of this quadratic equation:

$\begin{aligned}b^2 - 4\, a\, c &= (-(2\, p + 1))^2 - 4\, p\, (p + 2) \\ &= 4\, p^2 + 4\, p + 1 - 4\, p^2- 8\, p = -4\, p + 1\end{aligned}$ .

A quadratic equation has no real root if its quadratic discriminant is less then zero. As a result, this quadratic equation will have no real root when $-4\, p + 1 < 0$ . Solve for the range of $p$ :

$\displaystyle p > \frac{1}{4}$ .

4 0

3 years ago

What number am<br> I am a 2-digit number divisible by 4, 6, and 7.<br> What number am i

maw [93]

84
84/4=21
84/6=14
84/7=12

4 0

3 years ago