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2 years ago

-2x^2+bx -5 Determine the b-value that would ensure the function has two real root.

Mathematics

1 answer:

anastassius [24]2 years ago

8 0

Answer:

No solution

Step-by-step explanation:

Given is the quadratic function

y = -2x² + bx - 5

In order to have two real roots the discriminant should be posivive

D = - b² - 4ac
D = - b² - 4(-2)(-5) = - b² - 40

We need D > 0

-b² - 40 > 0
b² + 40 < 0
b² < - 40

There is no solution as b² is never negative

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Step-by-step explanation:

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3 years ago

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Answer:

Step-by-step explanation:

So we have the product of:

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