let
(hypotenuse ) c = 10 in
(perpendicular) a = 8 in
(base) b =?
By using Pythagoras theorem
c^2= a^2+b^2
(10)^2 = (8)^2 +(b)^2
100 = 64 +(b)^2
100- 64 = (b)^2
36 = (b)^2
√36 = b
6 = b
hence b= 6 in
Answer: correct answer is B.(2x+3y)(4x^2-6xy+9y^2)
8x^3 + 27y^3
(2x)^3+(3y)^3
(2x+3y)(4x^2-6xy+9y^2) <----answer
That is the answer. you can't simplify it.
In a statistical test, the null hypothesis to be made is
that the sample proportions do not have any significant differences, which
means an equal distribution. This is only rejected when the estimate is equal
or less than 0.95. But since in this case it is >0.95, so therefore the null
hypothesis is not rejected. Therefore:
<span>False</span>
Ii.First ,expand: 5(x-2)=32
5x-10=32
bring 10 to the other side (add it to 32)
5x=42
divide both sides by 5 to get x
x=42/5
x=8.4
iii.Expand 5+2(x+3)=21
5+2x+6=21
bring 5 and 6 to the other side
2x=21-5-6
2x=10 divide both sides by 2
x=5
