Answer:
Area of tissue paper is 384 square inches.
Step-by-step explanation:
Given:
Length of box = 16 inches.
Width of the box = 12 inches.
We need to find find the area of the tissue paper.
But It is given that the area of the tissue paper sheet is based on twice the length times the width of the box.
Hence Framing in equation form we get;
Area of tissue paper = 
Hence Substituting the given values we get;
Area of tissue paper = 
Hence Area of tissue paper is 384 square inches.
Answer:
The exponential equation is;
y = 0.1•0.5^x
Step-by-step explanation:
Here, we want to get the exponential function represented by the table
Mathematically, the general form of an exponential function is;
y = a•b^x
By getting a and b, we have the exponential function
We can use any of the points;
Let us start with (0,0.1)
0.1 = a•b^0
anything raised to zero is 1
0.1 = a * 1
a = 0.1
Now, we have a
Let us work with the second point to get b
The point is (1,0.05)
0.05 = 0.1•b^1
0.05 = 0.1b
b = 0.05/0.1
b = 0.5
Thus, we have the equation as;
y = 0.1•0.5^x
Answer:
Length = 18.099 ft
Width = 11.049 ft
Step-by-step explanation:
let the length of the field be x ft
and the width be y ft
as per the condition given in problem
x=2y-4 -----------(A)
Also the area is given as 200 sqft
Hence
xy=200
Hence from A we get
y(2y-4)=200
taking 2 as GCF out
2y(y-2)=200
Dividing both sides by 2 we get


subtracting 100 from both sides

Now we solve the above equation with the help of Quadratic formula which is given in the image attached with this for any equation in form

Here in our case
a=1
b=-1
c=-100
Putting those values in the formula and solving them for y


Solving first





Solving second one






Which is wrong as the width can not be in negative
Our width of the field is
y=11.099
Hence the length will be
x=2y-4
x=2(11.049)-4
x=22.099-4
x=18.099
Hence our length x and width y :
Length = 18.099 ft
Width = 11.049 ft
5y+4x
5(10) + 4(-5)
50 - 20
30
Answer:
Step-by-step explanation:
hello : here is an solution