Answer:
1. Joelle spent 1¹/₂ hours reading and Rileigh spent 3/4 of that time.
To find out how much time Rileigh spent, multiply the fractions but first convert the improper fraction to a proper fraction:
= 1¹/₂ = 3/2
= 3/2 * 3/4
= 9/8
= 1¹/₈ hours
2. 1/10
3. They ate 1/6 of the donuts
They bought 18 donuts. 1/2 of 18 is 9. 1/3 of 9 is 3. To find the fraction, divide 3 by 18. Simplify the fraction. You are left with 1/6.
4. 2/3
1 1/3=4/3×1/2=4/6=2/3
And thats all on the pdf why are their only 4 Questions?
Step-by-step explanation:
Answer:
Step-by-step explanation:
= (12-8)/12 × 100%
= 4/12 × 100%
= 100/3%
= 33.33%
Answer:

Step-by-step explanation:
Given
Stot A:

Defective = 3%
Store B

Defective = 4%
Required
Determine the probability a product received is defective.
First, we calculate the probability that the defective product is from store A


Convert to decimals

Next, we calculate the probability that the defective product is from store B



The product may come from either stores.
So, the probability of having a defective product is:



Answer:
learn more d ko rin kc alam yan heheh
Answer:

And using the normal standard distribution or excel we got:

Step-by-step explanation:
Previous concepts
Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".
The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".
Solution to the problem
Let X the random variable that represent the weights of a population, and for this case we know the distribution for X is given by:
Where
and
Since the dsitribution for x is normal then we know that the distribution for the sample mean
is given by:
We want to find this probability:

And we can use the z score formula given by;

And if we find the z score for the limits given we got:


So we can calculate this probability like this:

And using the normal standard distribution or excel we got:
