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Goshia [24]
2 years ago
6

What is the force of the drag for a 65 kg bicyclist, initially at rest at the top of a hill coasts down the hill, reaching a spe

ed of 15.5 m/s at the bottom of the hill. The distance is 60M. neglect any friction impeding the motion and the rotational energy of the wheels.
Height is 19M
Intial GPE is 12350J

KE is 7808J and loss is 4542 J
Physics
1 answer:
Fofino [41]2 years ago
4 0
Who knows, not me, not me and not me again
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A car is stopped at a traffic light. When the light turns green at t=0, a truck with a constant speed passes the car with a 20m/
s344n2d4d5 [400]

Answer:

At t = (70 / 3) \; {\rm s} (approximately 23.3 \; {\rm s}.)

Explanation:

Note that the acceleration of the car between t = 0\; {\rm s} and t = 20\; {\rm s} (\Delta t = 20\; {\rm s}) is constant. Initial velocity of the car was v_{0} = 0\; {\rm m\cdot s^{-1}}, whereas v_{1} = 35\; {\rm m\cdot s^{-1}} at t = 20\; {\rm s}\!. Hence, at t = 20\; {\rm s}\!\!, this car would have travelled a distance of:

\begin{aligned}x &= \frac{(v_{1} - v_{0})\, \Delta t}{2} \\ &= \frac{(35\; {\rm m\cdot s^{-1}} - 0\; {\rm m\cdot s^{-1}}) \times (20\; {\rm s})}{2} \\ &= 350\; {\rm m}\end{aligned}.

At t = 20\; {\rm s}, the truck would have travelled a distance of x = v\, t = 20\; {\rm m\cdot s^{-1}} \times 20\; {\rm s} = 400\; {\rm m}.

In other words, at t = 20\; {\rm s}, the truck was 400\; {\rm m} - 350\; {\rm m} = 50\; {\rm m} ahead of the car. The velocity of the car is greater than that of the truck by 35\; {\rm m\cdot s^{-1}} - 20\; {\rm m\cdot s^{-1}} = 15 \; {\rm m\cdot s^{-1}}. It would take another (50\; {\rm m}) / (15\; {\rm m\cdot s^{-1}}) = (10/3)\; {\rm s} before the car catches up with the truck.

Hence, the car would catch up with the truck at t = (20 + (10/3))\; {\rm s} = (70 / 3)\; {\rm s}.

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2 years ago
Is the following sentence true or false? The lithospheric plates move at about 5 km per year
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About 2 to 5 centimeters per year (1 to 2 inches per year), about the same speed that your fingernails grow. Therefore, the statement is false
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I hope this helps.
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Why do the layers of sedimentary rocks parallel to earth's surface?​
Vedmedyk [2.9K]

Answer:

why do the layers of sedimentary rocks parallel to earth's surface?

Why are sedimentary rocks found on or close to Earth's surface?

Explanation: Erosion breaks existing rocks and turns them into sediments. ... When subjected to heat and pressure deeper in the earth sedimentary rocks are changed into igneous and metamorphic rocks. Because erosion only happens on the earth's surface sedimentary rocks are only formed on the earth's surface.

Explanation:

Why do sedimentary rocks have layers and how these layers are formed?

The different groups of sediments could have been deposited through wind, water, ice, and/or gravity at different intervals of time and compacted on top of each other, until they create a sedimentary rock that has several different types of sediments (possibly from different rock types) in the form of layers.

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Radiation: transferred energy
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