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artcher [175]
2 years ago
9

In outer space, a piece of rock continues moving at the same velocity for

Physics
1 answer:
Ray Of Light [21]2 years ago
7 0

The absence of external force in the outer space, allows the piece of rock to continue moving at the same velocity for thousands of years.

<h3>Absence of external force on the outer space</h3>

The outer space is almost an absolute vacuum, because it's nearly empty. There is no matter such as air in the outer space that will provide an external force needed to change the velocity of the piece of rock.

From Newton's first law of motion, an object in a state of rest or uniform motion in a straight line, will continue in that state unless it is acted upon by an external force.

Thus, the absence of external force in the outer space, allows the piece of rock to continue moving at the same velocity for thousands of years.

Learn more about outer space here: brainly.com/question/24701339

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Panel A shows a ball shortly after being thrown upward. Panel B shows the same ball in an instant on its way down. Suppose air r
Anna11 [10]

Answer:

ur mom

Explanation:

6 0
2 years ago
1. You get hit with a force of 45 N by a ball with a mass of 0.75 kg. How fast was the
dlinn [17]

Answer:

60 {ms}^{ - 2}

Explanation:

As we know,

=》Force = Mass × Acceleration

=》45 N = 0.75 × Acceleration

=》Acceleration = 45 ÷ 0.75

=》Acceleration = 60

hence, the Acceleration of the ball would be. 60 meters per second square

60m {s}^{ - 2}

6 0
3 years ago
The Law of the Conservation of Mass states that the mass of the products in a chemical reaction must equal the mass of the react
Stella [2.4K]
True (idk exactly why though)
6 0
3 years ago
Which value is equivalent to 178 centimeters?
tester [92]

178 centimeters is exactly, precisely, the same length as ...

-- 0.00178 kilometer
-- 1.78 meters
-- 1,780 millimeters
-- 1,780,000 micrometers
-- 1,780,000,000 nanometers

7 0
3 years ago
The moment of inertia of the empty turntable is 1.5 kg?m2. With a constant torque of 2.5 N?m, the turntableperson system takes 3
Tamiku [17]

6.0 \mathrm{kg} \mathrm{m}^{2} is the persons moment of inertia about an axis through her center of mass.

Answer: Option B

<u>Explanation:</u>

Given data are as follows:

moment of inertia of the empty turntable = 1.5

Torque = 2.5 N/m , and

           \text { Angular acceleration of the turntable }=\frac{\text { angular speed }}{\text { time }}=\frac{1}{3}

Let the persons moment of inertia about an axis through her center of mass= I

So, Now, from the formula of torque,

            \text { Torque }(\tau)=\text { Moment of inertia(I) } \times \text { Angular acceleration(a) }

            2.5=(1.5+I) \times \frac{1}{3}

So, from the above equation, we can measure the person’s moment of Inertia (I)

             2.5 \times 3=1.5+I

             I=7.5-1.5=6.0 \mathrm{kg} m^{2}

8 0
3 years ago
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