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Rudik [331]
2 years ago
6

A student uses a motion detector to study the kinematics of a block suspended on a vertical spring that obeys Hooke’s law. The s

tudent pulls the block a distance y from equilibrium, releases it from rest, and records the speed v of the block as it passes the equilibrium position. The student repeats this process several times for different values of y. Which variables should be plotted on the horizontal and vertical axes to yield a linear graph?
Physics
1 answer:
Digiron [165]2 years ago
5 0

When the speed of the block is plotted on the vertical axis and displacement of the block plotted on the horizontal axis, a linear graph will be obtained showing the inverse relationship between the speed of the block and the displacement of the block.

<h3>Hooke's law</h3>

Hooke's law states that force or load applied to elastic material is directly proportional to the extension produced in the material. This law can be written as;

F = kx

where;

  • F is the applied force
  • k is spring constant
  • x is extension of the material
<h3>Velocity of the block</h3>

The speed of the block increases with decreasing displacement of the bock. This is because the kinetic energy of the block is maximum at zero displacement and minimum at maximum displacement of the block.

Thus, when the speed of the block is plotted on the vertical axis and displacement of the block plotted on the horizontal axis, a linear graph will be obtained showing the inverse relationship between the speed of the block and the displacement of the block.

Learn more about Hooke's law here: brainly.com/question/2648431

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If x2 = 60, what is the value of x? plus or minus square root 30 plus or minus square root 60 ±30 ±120
Zielflug [23.3K]
X2 = 60
/ 2 / 2
x = 30
Plus or minus square root 60
4 0
3 years ago
How much work is done when a force of 15.0 newtons is used to lift a box 3.0 meters into the air?
denis-greek [22]

Added potential energy = (mass) x (gravity) x (height)

or

Added potential energy = (weight) x (added height)

If you need to lift a 15N box 3m straight up, you have to increase its potential energy by (15 N) x (3 m) = 45 Joules .

Where is that added potential energy supposed to come from ?  You could use an electric winch, a steam engine, a gasoline-powered motor, thousands of hamsters running on little treadmills that are are connected to the main pulley somehow, or your own arm muscles.  But howEVER you do it, you have to provide <em>45 Joules</em> of WORK in order to increase the potential energy of the box by just that much.  

8 0
3 years ago
Read 2 more answers
Two balls of equal mass collide and stick together as shown in the figure. The initial velocity of ball B is twice that of ball
Mice21 [21]

The angle above the horizontal of the motion of mass A + B after the collision. as well as others are mathematically given as

  • \theta f = 26.3 \deg
  • vf/vA= 0.94
  • 2vf^2 / 5vA^2 = 0.35

<h3>What is  Collison equilibrium?</h3>

According to the collision hypothesis of chemistry, chemical reactions happen when two molecules or atoms collide.

Generally, the equation for Collison equilibrium is  mathematically given as

For horizontal motion

mvAx+m2vAx = 2mvfx

For vertical motion

-mvAy+m2vAy = 2mvfy

vfy = 1/2 vAy

\tan \theta f = vfy/vfx \\\\\tan \theta f = 1/3 vAy/vAx \\\\\tan \theta f  = vAy/vAx \\\\\theta f = tan-1 ( 1/3 tan (56) )\\\\

\theta f = 26.3 \deg

(b)

v fy = vf sin \theta f\\\\vAy = vA sin theta i\\\\vf/vA = vfy/vAy sin( \theta i)/sin(\theta f)\\\\vf/vA = 1/2 sin(56)/sin(26.3) \\\\

vf/vA= 0.94

(c)

Ef/Ei = \frac{(1/2 * (2m) * (vf)^2) }{ (1/2 * m * (vA)^2) + 1/2*m*(2vA)^2) ]}

2vf^2 / 5vA^2 = 0.35

In conclusion, The angle above the horizontal of the motion of mass A + B after the collision. as well as others

\theta f = 26.3 \deg

vf/vA= 0.94

2vf^2 / 5vA^2 = 0.35

Read more about collision theory

brainly.com/question/20628781

#SPJ1

8 0
2 years ago
A 73-kg person in a moving car stops during a car collision in a distance of 0.80 m . The stopping force that the air bag exerts
fredd [130]

Answer:

 v₀ = 13.24 m / s

Explanation:

Let's use Newton's second law to find the average acceleration during the crash

       F = m a

.       a = F / m

       a = 8000/73

       a = 109.59 m / s²

Now we can use the kinematic equations to find the initial velocity, since when the velocity stops it is zero (v = 0)

       v² = v₀² - 2 a x

       v₀² = 2 a x

       v₀ = √  2 a x

       v₀ = √ (2 109.59 0.80)

       v₀ = 13.24 m / s

3 0
4 years ago
Read 2 more answers
If the x-component of velocity is 27m/s and the y-component of velocity is -23 m/s, what is the resultant vector?
Dafna11 [192]

Answer:

35.47 m/s

Explanation:

r =  \sqrt{( - 23)^{2}  + (27) ^{2} }

=35.57

5 0
3 years ago
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