X2 = 60
/ 2 / 2
x = 30
Plus or minus square root 60
Added potential energy = (mass) x (gravity) x (height)
or
Added potential energy = (weight) x (added height)
If you need to lift a 15N box 3m straight up, you have to increase its potential energy by (15 N) x (3 m) = 45 Joules .
Where is that added potential energy supposed to come from ? You could use an electric winch, a steam engine, a gasoline-powered motor, thousands of hamsters running on little treadmills that are are connected to the main pulley somehow, or your own arm muscles. But howEVER you do it, you have to provide <em>45 Joules</em> of WORK in order to increase the potential energy of the box by just that much.
The angle above the horizontal of the motion of mass A + B after the collision. as well as others are mathematically given as

- vf/vA= 0.94
- 2vf^2 / 5vA^2 = 0.35
<h3>What is
Collison equilibrium?</h3>
According to the collision hypothesis of chemistry, chemical reactions happen when two molecules or atoms collide.
Generally, the equation for Collison equilibrium is mathematically given as
For horizontal motion
mvAx+m2vAx = 2mvfx
For vertical motion
-mvAy+m2vAy = 2mvfy
vfy = 1/2 vAy


(b)

vf/vA= 0.94
(c)
![Ef/Ei = \frac{(1/2 * (2m) * (vf)^2) }{ (1/2 * m * (vA)^2) + 1/2*m*(2vA)^2) ]}](https://tex.z-dn.net/?f=Ef%2FEi%20%3D%20%5Cfrac%7B%281%2F2%20%2A%20%282m%29%20%2A%20%28vf%29%5E2%29%20%7D%7B%20%281%2F2%20%2A%20m%20%2A%20%28vA%29%5E2%29%20%2B%201%2F2%2Am%2A%282vA%29%5E2%29%20%5D%7D)
2vf^2 / 5vA^2 = 0.35
In conclusion, The angle above the horizontal of the motion of mass A + B after the collision. as well as others

vf/vA= 0.94
2vf^2 / 5vA^2 = 0.35
Read more about collision theory
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Answer:
v₀ = 13.24 m / s
Explanation:
Let's use Newton's second law to find the average acceleration during the crash
F = m a
. a = F / m
a = 8000/73
a = 109.59 m / s²
Now we can use the kinematic equations to find the initial velocity, since when the velocity stops it is zero (v = 0)
v² = v₀² - 2 a x
v₀² = 2 a x
v₀ = √ 2 a x
v₀ = √ (2 109.59 0.80)
v₀ = 13.24 m / s