Which part(s) of a hair can be analyzed for nuclear DNA?

Which feature of a chemical equation represents the law of conservation of mass?

N76 [4]

Answer:

it shows the products of a chemical reaction to the right of the reaction arrow

4 0

2 years ago

When point charges q = +8.4 uC and q2 = +5.6 uC are brought near each other, each experiences a repulsive force of magnitude 0.6

Stella [2.4K]

Answer:

it is separated by 80 cm distance

Explanation:

As per Coulombs law we know that force between two point charges is given by

$F = \frac{kq_1q_2}{r^2}$

here we know that

$q_1 = +8.4\mu C$

$q_2 = +5.6 \mu C$

force between two charges is given as

$F = 0.66 N$

now we have

$F = \frac{kq_1q_2}{r^2}$

$0.66 = \frac{(9\times 10^9)(8.4 \mu C)(5.6 \mu C)}{r^2}$

$r = 0.8 m$

so it is separated by 80 cm distance

3 0

2 years ago

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What is the motion of the object?

aleksley [76]

Answer:

Thus, the object is accelerating to the left

Explanation:

The Net Force

The net force is the result of adding all the forces as vectors acting on a body.

$\vec F=\vec F_1+\vec F_2+...+\vec F_n$

Each vector can be expressed in its rectangular components Fx and Fy, and the sum is the sum of the rectangular components separately.

Second Newton's law gives the relation between the net force and the acceleration of the body:

$\vec F = m.\vec a$

We can see the acceleration is a vector with the same direction as the net force.

The diagram shows two vertical forces and two horizontal forces.

The vertical forces are acting in opposite directions and with the same magnitude, thus they cancel out, leaving zero net force in the y-axis.

The horizontal forces are opposite and with different magnitudes. Since the force acting to the left (F3) has a greater magnitude than the force acting to the right (F4), there is a net force directed to the left with a magnitude of 60 N - 20 N = 40 N

Thus, the object is accelerating to the left

4 0

3 years ago

A car is traveling at 15m/s on a horizontal road. the brakes are applied and the car skids to a stop in 4.0s . the coefficient o

iren2701 [21]

Answer:

the coefficient of Kinetic friction between the tires and road is 0.38

Option A) .38 is the correct answer

Explanation:

Given that;

final velocity v = 0

initial velocity u = 15m/s

time taken t = 4 s

acceleration a = ?

from the equation of motion

v = u + at

we substitute

0 = 15 + a × 4

acceleration a = -15/4 = - 3.75 m/s²

the negative sign tells us that its a deacceleration so the sign can be ignored.

Deacceleration due to friction a = μ × g

we substitute

3.75 = μ × 9.8

μ = 3.75 / 9.8 = 0.3826 ≈ 0.38

Therefore the coefficient of Kinetic friction between the tires and road is 0.38

Option A) .38 is the correct answer

8 0

2 years ago

The impact time for a particular collision is 3.0 x 10^-3 seconds and the impulse in the collision is 0.30 newton seconds. What

BartSMP [9]

Answer

C.) 1.0 x 10^2 Newton’s

Explanation

The Newton's second law of motion states that, the rate of change of momentum is proportional to the force producing it.

∴ F = (mv- mu)/t

Ft = mv - mu.

The quantity Ft is called the impulse.

Ft = 0.30 Newton seconds

but t = 3.0 x 10⁻³ seconds

Ft = 0.30 Ns

F × 3.0 x 10⁻³ = 0.30 Ns

F = 0.30 / (3.0 x 10⁻³)

= 100 N

Answer = C.) 1.0 x 10^2 Newton’s

8 0

3 years ago

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