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Nostrana [21]
2 years ago
8

For a 1 efficient step down transformer voltage in primary and secondary are equal current in primary and secondary are equal in

put power is same as the output power output power is zero
Physics
1 answer:
Fynjy0 [20]2 years ago
5 0

The given condition for a 100% efficient  step down transformer is not true.

<h3>How do Step-down Transformers work?</h3>

Because there are fewer turns in the secondary winding of a step-down transformer, the secondary voltage is lower than the initial voltage. As a result, this kind of transformer is employed to reduce the voltage to the levels intended for the circuit. Almost all power supply incorporate a step-down transformer to keep the operating voltage range of the circuit within acceptable limits. Electronic transformers and distribution systems are often where these transformers are installed (power transformers).

<h3>What Does a Step-Down Transformer Mean by Power?</h3>

Using the system voltage and current, we can calculate the power of a transformer. Volt-Amps, or VA, is the unit used to measure the power in a transformer (for larger transformers Kilo Volt-Amps, kVA).

Any transformer should, in theory, have constant power on both sides, which implies that the power available on the secondary side of the transformer should match the power available on the primary side. This also applies to step-down transformers. A step-down transformer's secondary side has a lower voltage than its primary side, hence in order to balance the transformer's total power, the secondary current would need to be increased.

<h3>What is the Step-Down Transformer's Relationship Between Voltage and Current?</h3>

In a step-down transformer, the output current is greater than the input current while the output voltage is lower than the primary voltage.

To know more about step down transformer visit:

brainly.com/question/7551270

#SPJ4

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If 61.4 cm of copper wire (diameter = 1.08 mm, resistivity = 1.69 × 10-8Ω·m) is formed into a circular loop and placed perpendic
harkovskaia [24]

Answer:

the thermal energy generated in the loop = 6.64*10^{-4}  \ W

Explanation:

Given that;

The length of the copper wire L = 0.614 m

Radius of the loop  r = \frac{L}{2 \pi}

r = \frac{0.614}{2 \pi}

r = 0.0977 m

However , the area of the loop is :

A_L = \pi r^2

A_L = \pi (0.0977)^2

A_L = 0.02999 \ m^2

Change in the magnetic field is \frac{dB}{dt}= 0.0914 \ T/s

Then the induced emf e = A_L \frac{dB}{dt}

e = 0.02999 * 0.0914

e = 2.74 × 10⁻³ V

resistivity of the copper wire \rho = 1.69* 10^{-8} Ω m

diameter of the wire = 1.08 mm

radius of the wire = 0.54 mm = 0.54 × 10⁻³  m

Thus, the resistance of the wire  R = \frac {\rho L}{\pi r^2}

R =  \frac{(1.69*10^{-8})(0.614)}{   \pi (0.54*10^{-3})^2}

R = 1.13× 10⁻² Ω

Finally,  the thermal energy generated in the loop (i.e the power) = \frac{e^2}{R}

= \frac{(2.74*10^{-3})^2}{1.13*10^{-2}}

= 6.64*10^{-4}  \ W

8 0
3 years ago
A satellite in earth orbit has a mass of 99 kg and is at an altitude of 2.02 106 m. (assume that u = 0 as r â â.) (a) what is th
Ierofanga [76]

(a)          What is the potential energy: PE = -G * M * m/r

 

Where: M is the mass of the earth which is 5.98 * 10^24 kg.

m is the mass of the satellite.

r is the space from the center of the earth to the satellite

 

To conclude this distance add the radius of the earth to the altitude. Radius of the earth is 6.38 * 10^6 meters.

 

 

r = 6.38 * 10^6 + 2.02 * 10^6 = 8.38 * 10^6

PE = 6.67 * 10^-11 * 5.98 * 10^24 * 99/8.38 * 10^6 = 4.71240095 * 10^9 J

 

 

(b) magnitude of the gravitational force exerted by the Earth

 

Fg = G * M * m/r^2

Fg = 6.67 * 10^-11 * 5.98 * 10^24 * 99/(8.38 * 10^6)^2 = 562.3078873 N

 

 

(c) There are no other forces that the satellite exert on the Earth. So therefore, it is 0.

8 0
4 years ago
RESPIRATION the exchange of gases between your body and your environment.<br> TRUE OR FALSE
Karo-lina-s [1.5K]

true

Explanation:

because in physiology, respiration is the movement of oxygen from the outside environment to the cells within tissues, and the removal of carbon dioxide in the opposite direction.

7 0
3 years ago
What graph would best represent acceleration as a function of mass when a constant force is applied?
Alex17521 [72]

The graphs of the acceleration as a function of mass and of the acceleration as a function of force are in attachment.

Explanation:

To answer both parts of the question, we refer to Newton's second law, which states that:

F=ma

where

F is the net force on an object

m is the mass of the object

a is its acceleration

a)

To answer this part, we re-arrange the previous equation as follows:

a=\frac{F}{m}

Therefore, we notice that if a constant force is applied, the acceleration is inversely proportional to the mass of the object:

a \propto \frac{1}{m}

this means that if the mass increases, the acceleration decreases, and if the mass decreases, the acceleration increases.

In a graph of acceleration vs mass, the curve representing this relationship would be a hyperbole. The graph is shown as the first graph in the attached picture.

b)

As before, we re-arrange the previous equation as follows:

a=\frac{F}{m}

Here we notice that if the object has a constant mass, the acceleration is directly proportional to the force applied on the object:

a \propto F

this means that when the force increases, the acceleration increases, and when the force decreases, the acceleration decreases.

In a graph of acceleration vs force, the curve representing this relationship would be a straight line, as shown in the second graph in the attached picture.

Learn more about Newton's second law of motion here:

brainly.com/question/3820012

#LearnwithBrainly

6 0
3 years ago
An electromagnetic wave is transporting energy in the negative y direction. At one point and one instant the magnetic field is i
natali 33 [55]

Answer:. Option c

Explanation: the speed of an electromagnetic wave is simply the vector product of the magnetic field and the electric field.

The direction of the velocity is the direction of the electromagnetic wave.

The wave is already moving towards the negative y axis (-j) and the magnetic field is already pointing towards the positive x axis (i)

From cross product of unit vectors

i × j = k

i × k = - j

With the second identity, we can see that the electric field will be pointing towards the positive of the x axis (k).

Option c is validated

4 0
3 years ago
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