How to get answer for number 1: | 4+2i |

How to get answer for number 2: | 5-i |

Number 3 how to get answer: | -3i |
![\left|a+bi\right|\:=\sqrt{\left(a+bi\right)\left(a-bi\right)}=\sqrt{a^2+b^2}\\\mathrm{With\:}a=0,\:b=-3\\=\sqrt{0^2+\left(-3\right)^2}\\Refine\\=\sqrt{9}\\\sqrt{9}\\\mathrm{Factor\:the\:number:\:}\:9=3^2\\=\sqrt{3^2}\\\mathrm{Apply\:radical\:rule}:\quad \sqrt[n]{a^n}=a\\\sqrt{3^2}=3\\= 3](https://tex.z-dn.net/?f=%5Cleft%7Ca%2Bbi%5Cright%7C%5C%3A%3D%5Csqrt%7B%5Cleft%28a%2Bbi%5Cright%29%5Cleft%28a-bi%5Cright%29%7D%3D%5Csqrt%7Ba%5E2%2Bb%5E2%7D%5C%5C%5Cmathrm%7BWith%5C%3A%7Da%3D0%2C%5C%3Ab%3D-3%5C%5C%3D%5Csqrt%7B0%5E2%2B%5Cleft%28-3%5Cright%29%5E2%7D%5C%5CRefine%5C%5C%3D%5Csqrt%7B9%7D%5C%5C%5Csqrt%7B9%7D%5C%5C%5Cmathrm%7BFactor%5C%3Athe%5C%3Anumber%3A%5C%3A%7D%5C%3A9%3D3%5E2%5C%5C%3D%5Csqrt%7B3%5E2%7D%5C%5C%5Cmathrm%7BApply%5C%3Aradical%5C%3Arule%7D%3A%5Cquad%20%5Csqrt%5Bn%5D%7Ba%5En%7D%3Da%5C%5C%5Csqrt%7B3%5E2%7D%3D3%5C%5C%3D%203)
Answer:
128
Step-by-step explanation:
8 - 5 x 3 x -2^3
8 - 5 x 3 x -8
8 - 15 x -8
8 - -120
128
Answer:

Step-by-step explanation:
We can rewrite the question as (x-5)*(x-5).
Using the FOIL Method (First, Outside, Inside, Last):

This simplifies to 
49–2ax –a^2–x^2
Extract the negative sign
= 49 - (a^2 +2ax +x^2)
Factor using a^2 + 2ab + b^2 = (a+b)^2
= 49 - (a+x)^2
Factor using a^2 - b^2 = (a-b)(a+b)
= ( 7- (a + x)) * (7 + (a + x))
= ( 7- a - x) * (7 + a + x)