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Vika [28.1K]
3 years ago
5

Distribute -2(c - 8)

Mathematics
2 answers:
Ulleksa [173]3 years ago
5 0

Answer:

<h2>-2c + 16-</h2>

Step-by-step explanation:

<h2>give me brainliest please</h2>

given:

-2(c-8)

-2(c) + -2(-8)

-2c + (--16)

-2c + (+16)

-2c+16

Nadya [2.5K]3 years ago
5 0

Answer:

Step-by-step explanation:

-2*c - (-2)*8 = -2c + 16

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The mean shoe size of the students in a math class is 7.5. Most of the shoe sizes fall within 1 standard deviation, or between a
Zarrin [17]

Answer:

1.5


Step-by-step explanation:

The mean is the Middle number.

1 standard deviation in both sides of 7.5 makes it between 6 and 9.

<u>What is the </u><u>"common difference"</u><u> in 6 to 7.5 and from 7.5 to 9?</u>

7.5-6=1.5

and

9-7.5=1.5


So, we would say the standard deviation is 1.5

Answer choice A is right.

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3 years ago
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Beth poured the same amount of juice into 10 glasses. She used 2 quarts of juice. How much juice is in each glass?
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Answer:

6.4 ounces

Step-by-step explanation:

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2 years ago
A real estate agent has 8 master keys to open several new homes. Only 1 master key will open any given house. If 40% of these ho
riadik2000 [5.3K]

Answer:

Step-by-step explanation:

Suppose F represents the value that a room is unlocked.

Then, we can assume that the probability of unlocked homes is:

P(unlocked homes) = P(U)

P(unlocked homes) = 40%

P(unlocked homes) = 0.40

Also, let us represent the value of the locked room with G.

P(locked homes) = P(G)

P(locked homes) = (1 - 0.40)

P(locked homes) = 0.60

Let the probability of selecting a correct key be P(S)

It implies that for the agent to use 3 keys, we have a combination of ^8C_3 possible ways for the set of keys.

Now; since only one will open the house, then:

P(select correct key) = P(S)

P(S) = \dfrac{ (^1_1) (^7_2)   }{   ^8_3 }

P(S) = \dfrac{21}{56}

P(S) = 0.375

Finally, for the real estate agent to have access to specific homes supposing the agent select three master keys at random prior to the time he left his office, Then:

P(F ∪ (G∩S) = P(F) + P(G∩S)

P(F ∪ (G∩S) = P(F) + P(G) × P(S)

P(F ∪ (G∩S) = 0.40 + (0.60×0.375)

P(F ∪ (G∩S) = 0.40 + 0.225

P(F ∪ (G∩S) =0.625

5 0
2 years ago
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