For this case we have the following equation:
Where,
w: The weight of a spring in pounds
E: the energy stored by the spring in joules.
Substituting values we have:
Making the corresponding calculation:
Answer:
the approximate weight of the spring in pounds is:
Answer:
5
Step-by-step explanation:
Answer:
x^3+6x^2+11x+12
Step-by-step explanation:
(x+4)(x^2+2x+3)
=x(x^2+2x+3)+4(x^2+2x+3) [by multiplying with bith sides]
=x^3+2x^2+3x+4x^2+8x+12
=x^3+2x^2+4x^2+3x+8x+12
=x^3+6x^2+11x+12
(please mark me brainliest)
Answer:
t = 9 s
Step-by-step explanation:
A stone is thrown downward with an intitial velocity of 29.5 m/sec will travel a distance of a meters, where
We need to find when the stone will hit the ground. It means when s(t) = 0. So,
So, the stone will take 9 seconds to hit the ground. Hence, this is the required solution.
The puppy runs a distance of D) 18 - 19 meters in one lap.
Step-by-step explanation:
Step 1; It is given that the leash measures 3 meters long. He runs pulling the leash as much as he can creating circles. Even though he keeps pulling, the leash will remain at a constant length of 3 meters. So we need to calculate the perimeter of the circle.
Step 2; The perimeter of any given circle is 2π times the radius. The radius of this circle is equal to 3 meters.
Perimeter of the circle = 2π × r = 2 × 3.1415 × 3 meters = 18.85 meters.
So the puppy runs a distance of 18.85 meters in a lap.
