The first step for solving this expression is to distribute -2 through the first parenthesis.
x - 2xy + 2y + 4xy - x × (3 + y)
Distribute -x through the second set of the parenthesis.
x - 2xy + 2y + 4xy - 3x - xy
Now collect together the like terms with a single x as a variable.
-2x - 2xy + 2y + 4xy - xy
Lastly,, collect the like term with an xy variable to find your final answer.
-2x + xy + 2y
Let me know if you have any further questions.
:)
The correct answer to this problem would be d
Answer:
1/5
Step-by-step explanation:
F(x)=x^2
g(x)=1/(2x+3)
g(f(-1))=?
x=-1→f(-1)=(-1)^2→f(-1)=1
g(f(-1))=g(1)=1/[2(1)+3]=1/(2+3)→g(f(-1))=1/5
Answer:
(a) 1/3
(b) 1/15
Step-by-step explanation:
(a)Let X denote the waiting time in minutes. It is given that X follows a uniform distribution, and since the variable being measured is time, we assume it to be a continuous uniform distribution.
![\[f_X(x) =\begin{cases} \frac{1}{30} & 0\leqx\leq 30\\ 0 & otherwise \end{cases}\]](https://tex.z-dn.net/?f=%20%5C%5Bf_X%28x%29%20%3D%5Cbegin%7Bcases%7D%20%5Cfrac%7B1%7D%7B30%7D%20%26%200%5Cleqx%5Cleq%2030%5C%5C%200%20%26%20otherwise%20%5Cend%7Bcases%7D%5C%5D)
Now
.
Jack or Rose arriving first is equally likely, therefore the probability of Jack waiting is just the half of the above obtained probability i.e 
(b)Using the formula for the expectation of a uniform continuous distribution,
