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3 years ago

PLEEEEEAAAASSSSSEEEEE HELP ME IM IN NEED OF ITTTTTT!!!!!!! IT'S URGENT

Mathematics

1 answer:

alina1380 [7]3 years ago

3 0

Going to answer this in the comments because my keyboard is covering my screen :(

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The legs of a right triangle have the lengths of 8 centimeters and 15 centimeters. What is the length of the hypotenuse, in cent

Anastasy [175]

Answer:

Step-by-step explanation:

WeknowthatsinceABCisarightangledtriangle,

AB2+BC2=AC2

82+152=AC2

64+225=AC2

AC2=289

AC=289−−−√=17

Hypotenuse=17cm

4 0

3 years ago

64 POINTS AWARDED, PLEASE ANSWER ASAP!!!!!

antoniya [11.8K]

Answer:

Area of rectangle = 40 square units

Step-by-step explanation:

Points to remember

Distance formula

Length of a line segment with end points (x₁, y₁) and (x₂, y₂) is given by,

Distance = √[(x₂ - x₁)² + (y₂ - y₁)²]

Area of rectangle = Length * Breadth

To find the length and breadth

Here a rectangle with vertices at (7, 3), (12, 3), (12, 11), and (7, 11)

Length1 = √[(x₂ - x₁)² + (y₂ - y₁)²]

√[(12 - 7)² + (3 - 3)²] = √5² = 5

Length2 = √[(x₂ - x₁)² + (y₂ - y₁)²]

√[(12 - 12)² + (11 - 3)²] = √8² = 8 units

Therefore Length of rectangle = 8 and

Breadth of rectangle = 5 units

To find the area of rectangle

Area = Length * Breadth

= 8 * 5 = 40 square units

8 0

3 years ago

Read 2 more answers

What is the simplified form of the following expression? 7(^3 square root 2x) - 3 (^3 square root 16x) -3 (^3 square root 8x)

Pachacha [2.7K]

Answer:

The third option listed: $\sqrt[3]{2x} -6\sqrt[3]{x}\\$

Step-by-step explanation:

We start by writing all the numerical factors inside the qubic roots in factor form (and if possible with exponent 3 so as to easily identify what can be extracted from the root):

$7\sqrt[3]{2x} -3\sqrt[3]{16x} -3\sqrt[3]{8x} =\\=7\sqrt[3]{2x} -3\sqrt[3]{2^32x} -3\sqrt[3]{2^3x} =\\=7\sqrt[3]{2x} -3*2\sqrt[3]{2x} -3*2\sqrt[3]{x}=\\=7\sqrt[3]{2x} -6\sqrt[3]{2x} -6\sqrt[3]{x}$

And now we combine all like terms (notice that the only two terms we can combine are the first two, which contain the exact same radical form:

$7\sqrt[3]{2x} -6\sqrt[3]{2x} -6\sqrt[3]{x}=\\=\sqrt[3]{2x} -6\sqrt[3]{x}$

Therefore this is the simplified radical expression: $\sqrt[3]{2x} -6\sqrt[3]{x}\\$

5 0

3 years ago

10 POINTS + BRAINLIEST TO FIRST CORRECT ANSWER!!! THANK YOU!

Fofino [41]

Answer:

The answer is A (Look at the graph of the relationship. Find the y-value of the point that corresponds to x = 1. That value is the unit rate)

Step-by-step explanation:

Because the proportional relation is defined by k = $\frac{y}{x}$ . If ratio is $\frac{units}{1unit}$ then it is a rate. Unit rate means per 1 unit such as $\frac{amountofmoney}{1kg}$ or $\frac{km}{1hour}$ thus the correct answer is A.

3 0

3 years ago

To make these Quadrilaterals similar what is the coordinate of S ???

Lilit [14]

ABCD 1234 AEIOU = meow meow i’m not a cow who who

6 0

3 years ago