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4 years ago

How do you separate iron filings toothpicks sand sugar chalk powder small pebbles

1 answer:

4 0

Following strategy can be used to separate the mixture containing sand, pebbles, iron fillings , sugar , tooth picks and chalk powder.

Step 1: HAND PICKING: Herein, the pebbles and tooth picks can be separated by hand-picking method.
Step 2: MAGNETIC SEPARATION: Herein, iron fillings are separated, as they are attracted towards magnet.
Step 3: Dissolution and Filtration: Water is added to sand, sugar and chalk powder. Sugar will dissolved, but sand and chalk and sand are insoluble in water.
Step 4: Sedimentation and Decantentation: Sand will settle down in water, hence, can be removed via sedimentation and decantentation.
Step 5: Filtration: Chalk powder is insoluble in water, hence it can be removed by filtration method.
Step 6: Crystallization: Sugar can be separated from solution by crystallization.

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What is the vowel.????????????

Serhud [2]

Answer:

a e i o u

Explanation:

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3 0

3 years ago

PLEASE HELP FAST IM ABOUT TO FAIL PLEASE HELP PLEASE HELP FAST HELP HELP THIS IS DESPRATE

MariettaO [177]

1. 0.240 liters of water would be needed to dissolve 21.6 g of lithium nitrate to make a 1.3 M (molar) solution.

2. 2.9 M is the molarity of a solution made of 215.1 g of HCl is dissolved to make 2.0 L of solution.

3.83.3 ml of concentrated 18 M H2SO4 is needed to prepare 250.0 mL of a 6.0 M solution.

4. 135 ml of stock HBr will be required to dilute the solution.

5. 150 ml of water should be added to 50.0 mL of 12 M hydrochloric acid to make a 4.0 M solution

6. The pH of the resulting solution is 13.89

Explanation:

The formula used in solving the problems is

number of moles= $\frac{mass}{atomic mass of one mole}$ 1st equation

molarity = $\frac{number of moles}{volume}$ 2nd equation

Dilution formula

M1V1 = M2V2 3rd equation

1. Data given

mass of Lithium nitrate = 21.6 grams

atomic mass of on emole lithium nitrate = 68.946 gram/mole

Molarity is given as 1.3 M

VOLUME=?

Calculate the number of moles using equation 1

n = $\frac{21.6}{68.946}$

= 0.313 moles of lithium nitrate.

volume is calculated by applying equation 2.

volume = $\frac{0.313}{1.3}$

= 0.240 litres of water will be used.

2. Data given:

mass of HCl = 215.1 gram

atomic mass of HCl = 36.46 gram/mole

volume = 2 litres

molarity = ?

using equation 1 number of moles calculated

number of moles = $\frac{215.1}{36.46}$

number of moles of HCl = 5.899 moles

molarity is calculated by using equation 2

M = $\frac{5.899}{2}$

= 2.9 M is the molarity of the solution of 2 litre HCl.

3. data given:

molarity of H2SO4 = 18 M

Solution to be made 250 ml of 6 M

USING EQUATION 3

18 x V1= 250 x 6

V1 = 83.3 ml of concentrated 18 M H2SO4 will be required.

4. data given:

M1= 10M, V1 =?, M2= 3 ,V2= 450 ml

applying the equation 3

10 x VI = 3x 450

V1 = 135 ml of stock HBr will be required.

5. Data given:

V1 = 50 ml

M1= 12 M

V2=?

M2= 4

applying the equation 3

50 x 12 = 4 x v2

V2 = 150 ml.

6. data given:

HCl + NaOH ⇒ NaCl + H20

molarity of NaOH = 0.525 M

volume of NaOH = 25 ml

molarity of acid HCl= 75 ml

volume of HCl = 0.335 ml

pH=?

Number of moles of NaOH and HCl is calculated by using equation 1 and converting volume in litres

moles of NaOH = 0.0131

moles of HCl= 0.025 moles

The ratio of moles is 1:1 . To find the unreacted moles of acid and base which does not participated in neutralization so the difference of number of moles of acid minus number of moles of base is taken.

difference of moles = 0.0119 moles ( NaOH moles is more)

Molarity can be calculated by using equation 1 in (25 +75 ml) litre of solution

molarity = $\frac{0.0119}{0.1}$

= 0.11 M (pOH Concentration)

14 = pH + pOH

pH = 14 - 0.11

pH = 13.89

3 0

3 years ago

10. In one sample of Terne plate, the following ingredients were found lead(75%), tin (25%). Identify solvent and solute.

goblinko [34]

3 Solvent-lead, Solute-tin

5 0

3 years ago

Classify each of the following as a Strong acid (sa) or a Weak acid (wa) and indicate how each should be written in aqueous solu

ziro4ka [17]

Answer:

1. nitric acid: sa

2. perchloric acid: sa

3. hydrofluoric acid: wa

Explanation:

A strong acid (sa) is the one that is completely dissociated into ions in water. Conversely, a weak acid (wa) is not completely dissociated in water.

From the options, the strong acids are:

1. nitric acid (HNO₃). It dissociates completely into ions when is dissolved in water, as follows:

HNO₃ → H⁺ + NO₃⁻

2. perchloric acid (HClO₄). It is completely dissociated in water as follows:

HClO₄ → H⁺ + ClO₄⁻

The weak acid is hydrofluoric acid (HF). In water, only a small proportion is dissociated into ions. The proportion of ions formed is given by the equilibrium constant Ka. The dissociation is written by using double arrows:

HF ⇄ H⁺ + F⁻

4 0

3 years ago

Why is it easier to switch to solar and wind energy as compared to other alternative energy sources? Select all that apply.

hammer [34]

Answer:C. They can be produced easily in areas with geothermal activity.

D. The land can be used for other purposes while supplying energy.

Explanation:

Both c and d are correct

4 0

3 years ago