Y = e^tanx - 2
To find at which point it crosses x axis we state that y= 0
e^tanx - 2 = 0
e^tanx = 2
tanx = ln 2
tanx = 0.69314
x = 0.6061
to find slope at that point first we need to find first derivative of funtion y.
y' = (e^tanx)*1/cos^2(x)
now we express x = 0.6061 in y' and we get:
y' = k = 2,9599
<u>Given</u>:
Given that an aquarium is being filled with water.
The given graph shows the height of the water over time as the aquarium is being filled.
We need to determine the slope of the graph.
<u>Slope</u>:
The slope of the given graph can be determined using the formula,

Since, the slope is same for all the points on the straight line, then let us consider the points (2,5) and (4,10)
Substituting these points in the above formula, we get;

Simplifying, we get;


Thus, the slope of the given graph is 2.5
<em>PQR with vertices P(–2, 9), Q(7, –3), and R(–2, –3)</em>
<em>first distance P(–2, 9), Q(7, –3) </em>
<em>The distance (d) between two points is given by the following formula: </em>
<em>Answer= 15</em>
30/100 = 15/x
cross multiply
1500 = 30x
1500/30 = 50