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2 years ago

Find the solution to the following system using substitution or elimination:

Mathematics

2 answers:

Olegator [25]2 years ago

6 0

Answer:

Step-by-step explanation:

y = - x + 10 → (1)

y = 7x + 2 → (2)

Substitute y = 7x + 2 into (1)

7x + 2 = - x + 10 ( add x to both sides )

8x + 2 = 10 ( subtract 2 from both sides )

8x = 8 ( divide both sides by 8 )

x = 1

Substitute x = 1 into either of the 2 equations and solve for y

Substituting into (2)

y = 7(1) + 2 = 7 + 2 = 9

solution is (1, 9 ) → B

Mekhanik [1.2K]2 years ago

6 0

The answer is b have a great day

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a recipe calls for 3 cups of flour and 2 cups of sugar if you only have 2.5 cups of sugar to keep it proportional how much sugar

belka [17]

Answer:

You would need to use 2.4 cups of sugar if you have 2.5 cups of flour.

Step-by-step explanation:

Divide: 3 divided by 2.5=1.2

Multiply: 1.2 times 2=2.4

Answer: 2.4 cups of sugar

Hope this helped!! :)

Brainliest?!?!

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8 0

3 years ago

(03.01 MC)

Kitty [74]

Answer:

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4 0

3 years ago

Please solve. 6(3 + 8) - 4/5

Gre4nikov [31]

G'Day mate! Here's the answer:

53 1/3

1. 6(3 + 6) - 4/5

2. 6 x 3 is 18, and 6 x 8 is 48

3. 18 plus 48 is 66

4. 66 - 4/5 = 266/5

5. 266/5 as mixed number is 53 1/5

3 0

3 years ago

Read 2 more answers

A major cab company in Chicago has computed its mean fare from O'Hare Airport to the Drake Hotel to be $28.75 , with a standard

bulgar [2K]

Answer:

Following are the solution to the given choices:

Step-by-step explanation:

Using chebyshev's theorem :

$\to P(|(x-\mu)|\leq k \sigma)\geq 1- \frac{1}{k^2}\\\\here \\ \to \mu=28.75\\\\ \to \sigma=4.44$

In point a)

$\to |(x-\mu)|= |20.17-28.75|=8.58 and \sigma=4.44 \\\\so, \\k= \frac{ |(x-\mu)| }{\sigma}$

$= \frac{8.58}{4.44} \\\\ =1.9 \\\\ =2$

$value= (1- \frac{1}{k^2}) \times 100 \% =75\%$

In point b)

$\to (1- \frac{1}{k^2}) \times 100 \% =84\% \\\\\to (1- \frac{1}{k^2})=0.84 \\\\\to \frac{1}{k^2} =0.16 \\\\\to \frac{1}{k}=0.4\\\\ \to k=2.5 \\\\\to |(x-\mu)| \leq k \sigma \\\\= |(x-\mu)|\leq 2.5 \times 4.44 \\\\ = |(x-\mu)|\leq 1.11 \\\\ = (28.75\pm 11.1) \\\\\to \text{fares lies between}(17.65,39.85)$

In point c)

$\to 99.7 \% \\ lie \ between=28.75 \pm z(.03)\times \sigma \\\\ =28.75\pm 2.97 \times 4.44\\\\=(28.75\pm 13.1)\\\\=(15.65,41.85)\\$

In point d)

using standard normal variate

$x=20.17\\\\ z=-2 \\\\x=37.13\\\\ z=2\\\\\to P(20.17$

8 0

3 years ago

Is 4/7 greater or less than 3/5

baherus [9]

No, it is not.

4/7 ≈ 0.5714

3/5 = 0.6

Actually, 3/5 is greater than 4/7.

Another way you could do this is by multiplying 4/7 with 5/5 and by multiplying 3/5 with 7/7.

4/7 * 5/5 = 20/35

3/5 * 7/7 = 21/35

Have an awesome day! :)

6 0

3 years ago