Answer: A & C
<u>Step-by-step explanation:</u>
HL is Hypotenuse-Leg
A) the hypotenuse from ΔABC ≡ the hypotenuse from ΔFGH
a leg from ΔABC ≡ a leg from ΔFGH
Therefore HL Congruency Theorem can be used to prove ΔABC ≡ ΔFGH
B) a leg from ΔABC ≡ a leg from ΔFGH
the other leg from ΔABC ≡ the other leg from ΔFGH
Therefore LL (not HL) Congruency Theorem can be used.
C) the hypotenuse from ΔABC ≡ the hypotenuse from ΔFGH
at least one leg from ΔABC ≡ at least one leg from ΔFGH
Therefore HL Congruency Theorem can be used to prove ΔABC ≡ ΔFGH
D) an angle from ΔABC ≡ an angle from ΔFGH
the other angle from ΔABC ≡ the other angle from ΔFGH
AA cannot be used for congruence.
Answer:
30 and -3
Step-by-step explanation:
30 x -3=-90
30-3=27
Answer:
21110
Step-by-step explanation:
Answer:
A
Step-by-step explanation:
The segment BC joining the midpoints of 2 sides of the triangle is
Half the length of the third side, that is
x + 31 = 2(x + 19)
x + 31 = 2x + 38 ( subtract x from both sides )
31 = x + 38 ( subtract 38 from both sides )
- 7 = x → A
Answer:
ithink its a or c
Step-by-step explanation:
not sure but dang what grade u in??
