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2 years ago

Larry earns $5.25 per hour helping his neighbor. Last month he earned $220.50. How many

1 answer:

8 0

He worked 42 hours.
Explanation: If he earns $5.25/ hr you would divide the amount of money he earned by 5.25 which equals 42. By doing this you are finding out how many times 5.25 (how much he makes in ONE hour) goes into 220.50 therefore finding out how many hours he worked.

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the tile shown has a side length of 10.5 inches what power can you write to represent the area of the tile

Sliva [168]

You could not do that then you would gey 110.25 which is what is not the question

5 0

3 years ago

Brainliest answer!

pickupchik [31]

She added the check fee instead of subtracting it

8 0

3 years ago

<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7Bx%2B1%7D%20%2B%20%5Cfrac%7B4%7D%7Bx%2B4%7D%20-%20%5Cfrac%7B5%7D%7Bx%2B5%3C

Anna11 [10]

[ ( x + 4 )( x + 5 ) + 4( x + 1 )( x + 5) - 5( x + 1 )( x + 4 ) ] / [( x + 1 )( x + 4)( x + 5 )] = ( x^2 + 9x + 20 + 4x^2 + 24x +20 - 5x^2 - 25x - 20) / [( x + 1 )( x + 4)( x + 5 )] =
( - 2x + 20 ) / [( x + 1 )( x + 4)( x + 5 )] = ( - 2)( x - 10) / [( x + 1 )( x + 4)( x + 5 )]

4 0

3 years ago

you drop a ball from a height of 98 feet. at the same time, your friend throws a ball upward. the polynomials represent the heig

Ostrovityanka [42]

a) $h_0 -u_y t$

b) See interpretation below

Step-by-step explanation:

The motion of both balls is a free-fall motion: it means that the ball is acted upon the force of gravity only.

Therefore, this means that the motion of the ball is a uniformly accelerated motion, with constant acceleration equal to the acceleration of gravity:

$g=32 ft/s^2$

in the downward direction.

For the ball dropped from the initial height of $h_0 = 98 ft$ , the height at time t is given by

$h(t) = h_0 -\frac{1}{2}gt^2$ (1)

The ball which is thrown upward from the ground instead is fired with an initial vertical velocity $u_y$ , and its starting height is zero, so its position at time t is given by

$h'(t)=u_y t - \frac{1}{2}gt^2$ (2)

Therefore, the polynomial that represents the distance between the two balls is:

$h(t)-h'(t)=h_0 - \frac{1}{2}gt^2 - (u_y t - \frac{1}{2}gt^2) = h_0 -u_y t$

Now we interpret this polynomial, which is:

$\Delta h(t) = h_0 -u_y t$

which represents the distance between the two balls at time t.

The interpretation of the two terms is the following:

- The constant term, $h_0$ , is the initial distance between the two balls, at time t=0 (in fact, the first ball is still at the top of the building, while the second ball is on the ground). For this problem, $h_0 = 98 ft$

- The coefficient of the linear term, $u_y$ , is the initial velocity of the second ball; this terms tells us that the distance between the two balls decreases every second by $u_y$ feet.

5 0

3 years ago

Answer this pls need it

andrey2020 [161]

Answer:

Woah im sorry buh it luks complicated ill try nd wk on it to help u out

7 0

3 years ago