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alekssr [168]
3 years ago
15

BIG IDLAS MATH

Mathematics
1 answer:
Serhud [2]3 years ago
7 0

Answer:

Step-by-step explanation:

9.23

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koban [17]

FACTOR ALL OF THE EQUATIONS INTO "y = (x-h)^2 + k," AND THE EQUATION'S VERTEX IS (h,k)

10. y = (x+2)^2 - 11 --> (-2, -11)

11. y = -(x-4)^2 + 32 --> (4, 32)

12. y = 3(x-1)^2 - 5 --> (1, -5)

13. y = -2(x+2)^2 + 5 --> (-2, 5)

14. y = 2(x+1)^2 - 1 --> (-1, -1)

15. y = -5(x-1)^2 + 8 --> (1, 8)

16. y = 3(x-3)^2 - 26 --> (3, -26)

17. y = (x+5)^2 - 32 --> (-5, -32)

18. y = -(x-3)^2 + 10 --> (3, -10)

3 0
3 years ago
How does a set of integers differs from the set of whole numbers ? Please help
MariettaO [177]
The difference between set of whole numbers and a set of integers is that:

Whole numbers = {0, 1, 2, 3, 4, 5...}
Integers = {..., -5, -4, -3, -2, -1, 0, 1, 2, 3, 4, 5...}

If we name contents of the first set as n, in the second set you can have 2n-1 numbers (because we count 0 only once in both sets).
7 0
3 years ago
How many times does seven go into three hundred ninety four
Nookie1986 [14]

Answer: 56 times.

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394/7 = 56.3

56 * 7 = 392

392 + 7 = 399

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6 0
3 years ago
Read 2 more answers
Please help fix my answers this is do tomorrow :( . all the circled ones. Greatly appreciated
Dmitry_Shevchenko [17]
#3 is correct at 120.4

#4 is 15/8...because 3/4+3/4=6/4 (for 20 doors) plus 3/8 (which is half of 3/4 for 5 more doors) equals 15/8 gallons or 1.875 gallons

#5 is $812.50 because if 50 shares cost $125, 325 shares (125×6.5) equals 812.50
7 0
3 years ago
In the 1990s the demand for personal computers in the home went up with household income. For a given community in the 1990s, th
WITCHER [35]

Answer:

a) 0.5198 computers per household

b) 0.01153 computers

Step-by-step explanation:

Given:

number of computers in a home,

q = 0.3458 ln x - 3.045 ;   10,000 ≤ x ≤ 125,000

here x is mean household income

mean income = $30,000

increasing rate, \frac{dx}{dt} = $1,000

Now,

a) computers per household are

since,

mean income of  $30,000 lies in the range of 10,000 ≤ x ≤ 125,000

thus,

q = 0.3458 ln(30,000) - 3.045

or

q = 0.5198 computers per household

b) Rate of increase in computers i.e \frac{dq}{dt}

\frac{dq}{dt} = \frac{d(0.3458 ln x - 3.045)}{dt}

or

\frac{dq}{dt}=0.3458\times(\frac{1}{x})\frac{dx}{dt} - 0

on substituting the values, we get

\frac{dq}{dt}=0.3458\times(\frac{1}{30,000})\times1,000

or

= 0.01153 computers

6 0
3 years ago
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