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Andrei [34K]
3 years ago
12

Which two sets of angles are corresponding angles ?

Mathematics
1 answer:
Arte-miy333 [17]3 years ago
4 0
It is B I had my older brother take a look at this
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What is the value of x in the solution to this system of equations?
Airida [17]

Answer:

5 is the answer

Step-by-step explanation:

7 0
3 years ago
6.7 more than 5 times a number is 20
IrinaK [193]
Subtract 6.7 from 20. This is 13.3. Divide 13.3/5 is 2.66. That is the answer
6 0
3 years ago
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If you multiply two decimals less than 1,can you predict whether the product will be less or greater than either of the factors?
jek_recluse [69]
You can predict that it will be less then either of the factors. if you take half of half from anything will you ever have more than half of the original. 
-i know its a little confusing its the best i could come up with

4 0
3 years ago
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If 10^x = 5, what is x?
Valentin [98]

Answer:

x=0.69897009

Step-by-step explanation:

expand by logarithms

10^x=5

=log(10^x)=log(5)

=x log(10)=log (5)

log base 10 of 10 is 1

x.l =log(5)

multiple bothside by 1

x=log(5)

x=0.6989709

6 0
3 years ago
To evaluate log2(3), Autumn reasoned that since log2(2) = 1 and log2(4) = 2, log2(3) must be the average of 1 and 2 and therefor
geniusboy [140]

Answer:

log₂(3) = 1.585 ≠ 1.5

Her thinking is not valid because the technique of average is valid only  if the graph of the function is a straight line, but the graph of the log function is not a straight line.

Therefore the values cannot be taken by average

Step-by-step explanation:

Given:

log₂(2) = 1

log₂(4) = 2

To evaluate :  log₂(3)

Now,

we know that

logₓ(y) = \frac{\log(y)}{\log(x)}        (Here the log has same base in the numerator and the denominator i.e 10)

therefore,

log₂(3) =  \frac{\log(3)}{\log(2)}

also,

log(2) = 0.3010

log(3) = 0.4771

thus,

log₂(3) =  \frac{0.4771}{0.3010}

or

log₂(3) = 1.585 ≠ 1.5

Her thinking is not valid because the technique of average is valid only  if the graph of the function is a straight line, but the graph of the log function is not a straight line.

Therefore the values cannot be taken by average

7 0
4 years ago
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