Answer:
arc AB = 70°
arc BC = 110°
arc ABC = 180°
arc CDB = 250°
Step-by-step explanation:
Since these angles are not inscribed, but are at the center point of the circle, the angles and arcs will be the same measure.
Solve for arc AB:
Angle AFB = 70°, so arc AB = 70°
Solve for arc BC:
Angle AFC is a straight angle so it is 180°. To find angle BFC, subtract angle AFB from 180°.
180 - 70 = 110°
Since angle BFC = 110°, arc BC = 110°
Solve for arc ABC:
Add arc AB and arc BC together.
70° + 110° = 180°
Solve for arc CDB:
There are 360° in a cirlce. To find arc CDB, subtract arc BC from 360°.
360° - 110° = 250°
Answer: 27x²yz + 3xz² - 2xy - 2y²z + 2yz²
<u>Step-by-step explanation:</u>
Use the distributive property.
3xz(9xy + z) - 2yz(x + y - z)
= 3xz(9xy) + 3xz(z) -2yz(x) -2yz(y) -2yz(-z)
= 27x²yz + 3xz² -2xy -2y²z +2yz²
1.301
Explanation:
Given:
and
Note that from the properties of logarithms,
50-(14+12+2(5)+2(2)+3)
50-(26+10+4+3)
50-43
7
Hope this Helps
