Answer:
2. 3/4, 50%, 1/4, 12.5%
Step-by-step explanation:
Work completed at the 4 sites = 1/4, 50%, 12.5%, 3/4
1/4 = 0.25
50%
= 50/100
= 0.5
12.5%
= 12.5/100
= 0.125
3/4
= 0.75
in order from greatest to least?
3/4, 50%, 1/4, 12.5%
1. 12.5%, 1/4, 50%, 3/4
2. 3/4, 50%, 1/4, 12.5%
3. 3/4, 12.5%, 1/4, 50%
4. 1/4, 50%, 3/4, 12.5%
The equation that can be used to determine the dimensions of the base of the doghouse is x² + 4x = 21
<h3>
What is the equation?</h3>
A quadratic equation is an equation that usually has a single variable and it is raised to the power of 2.
Area of a rectangle = length x width
x (4 + x) = 21
x² + 4x = 21
To learn more about quadratic equations , please check: brainly.com/question/27696091
#SPJ1
It’s the first one - 3x^2 - 3x+8 - 9/x+1
Answer:
40
Step-by-step explanation:
f(4) = 3(4²) - 2(4)
= 3(16) - 8
= 48 - 8
= 40
when x=4, f(x) = 40
Answer:
a)
in
b) 28 in
c) 784 in²
Step-by-step explanation:
Let the length be 'L'
and the radius be 'r'
Thus, according to the question
L + 2πr = 84 in
L = 84 - 2πr ............(1)
Volume of the cylinder, V = πr²L
substituting the value of L from 1, we get
V = πr²(84 - 2πr)
or
V = 84πr² - 2π²r³
for points of maxima, differentiating the above equation and equating it to zero

or
2(84)πr - 3(2)π²r² = 0
or
2πr(84 - 3πr) = 0
or
r = 0 and 84 - 3πr = 0
or
⇒ 3πr = 84
or
⇒ r =
in
since, the radius cannot be zero therefore, r = 0 is neglected
Therefore,
a) The radius of the largest cylindrical package =
in
b) from (2)
L = 84 - 2πr
or
⇒ L = 
or
⇒ L = 84 - 56 = 28 in
The length of the largest cylindrical package = 28 in
c ) The volume of the largest cylindrical package ,V = πr²L
= 
= 784 in²