Answer:
hello : f(h(g(x)))= (4x - 9) + 4 /(4x - 9)
Step-by-step explanation:
calculate : h(g(x))
h(g(x)) = h(x - 2) = 4 (x -2) -1 = 4x - 8 -1
h(g(x)) = 4x - 9
calculate : f(h(g(x)))
f(h(g(x))) = f (4x - 9) = (4x - 9) + 4 /(4x - 9)
Answer:
Yes, x(t)+C is also a solution of given equation.
Step-by-step explanation:
We are given that x(t) is a solution of the equation x'=f(x)
We have to show that x(t+c) is also a solution of given equation and check x(t)+c is a solution of equation.
Suppose x'=1
![\frac{dx}{dt}=1](https://tex.z-dn.net/?f=%5Cfrac%7Bdx%7D%7Bdt%7D%3D1)
![dx=dt](https://tex.z-dn.net/?f=dx%3Ddt)
Integrating on both sides
Then , we get
![x=t+c](https://tex.z-dn.net/?f=x%3Dt%2Bc)
Where C is integration constant.
Now, t replace by t+c
Then, we get
because c+C=K
Different w.r.t then we get
![x'=1](https://tex.z-dn.net/?f=x%27%3D1)
Therefore, x(t+c) is also solution because it satisfied the given equation.
Now, x(t)+C=t+(c+C)=t+L where L=c+C=Constant
Differentiate w.r.t time
Then, we get ![x'=1](https://tex.z-dn.net/?f=x%27%3D1)
Yes, x(t)+C is also solution of given equation because it satisfied given equation
Answer:
d
Step-by-step explanation:
<33
Answer:
-x^2+3x+3
Step-by-step explanation:
if the evaluated answer is correct (but my answer above is correct) it would be -4+6+3 then the answer would be 5 but I am not sure