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avanturin [10]
2 years ago
10

What is this pls help

Mathematics
1 answer:
Alex2 years ago
7 0
-4.5 or -4.3 i’m not really sure i’m just estimating
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Simplify this expression 16+28÷2-6/10-4*2
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Answer:

12

Step-by-step explanation:

16+14-6/10-8

30-6/2

24/2

12

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3 years ago
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Evaluate 2X^4+2x-17 for x=-3 <br>a. 139<br>b. 173 <br>c. 185<br>d. -173
gogolik [260]
The answer is A. 2(-3)^4+2(-3)-17 = 139.
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The owner of a pet shop predicts that 10 out of 20 new puppies are male. He randomly selects 10 of the puppies, and notes that a
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A, 10 of the new puppies are male and 10 are female

Step-by-step explanation:

Really this is the one that makes the most since because if 10 of the puppies are male, then 10 must be female.

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3 years ago
The area of a rectangle knitted blanket is 9x^2-6x-8. What are the possible dimensions of the blanket? Use factoring ​
Ilya [14]

Answer:

(3x-4) by (3x+2) or (-3x+4) by (-3x-2)

Step-by-step explanation:

To factor 9x^2-6x-8 we want to find the factors of 9 and the factors of -8 that when multiplied in sequence and then added give us -6.

factors of -8:

-8 & 1

8  & -1

-4  & 2

4  & -2

you might also want to remember that these can be flipped, so if you have -8 & 1 you can also have 1 &-8.

factors of 9:

9  &  1

-9  & -1

3  &  3

-3  &  -3

So now we just need to find numbers where

a & b are factors of 9 and c & d are factors of -8 and a*c+b*d=-6,

if that is the case then (ax+c)*(bx+d)=9x^2-6x-8

guess: 3 & 3 and -4 & 2

3*(-4) + 3*2=-12 +6 = -6

so one factoring is (3x-4)*(3x+2)

This means that one of the possible dimensions of the blanket is (3x-4) by (3x+2)

guess: -3 & -3 and 4 & -2

(-3)*4+(-3)*(-2)= -12+6 = -6

so another factoring is (-3x+4)*(-3x-2)

So you could also have a blanket with dimensions (-3x+4) by (-3x-2) but this might not make sense to do because, if you input positive numbers for x you will get negative dimensions which in the real world don't exist for a knitted blanket.

p.s sorry for the late response.

3 0
3 years ago
True or false (if false, give an explanation and sketch a counterexample:
lesantik [10]
5. If a point is equidistant from the endpoints of a segment, then it must be the midpoint of the segment. True

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