To the nearest ten, 829 would become <em><u>830</u></em> because the ones digit (9) is closer to 30 than it is to 20. So we would round up.
To round to the nearest hundred, we look at the tens and ones digit. 29 is less than 50 so we would have to round down to <em><u>800</u></em> instead of rounding up to 900.
Hope that helps :)
F(-3) = 4(-3) - 3 = -12 - 3 = -15.
H(2) = -5(2) + 7 = -10 + 7 = -3.
F(-3) + H(2) = -15 + -3 = -18.
The solution is -18.
Answer:
6i
Step-by-step explanation:
First, I think you mean square root 18 and square root 2. (Let me know if thats right.)
Thus we have square root -36, which is simplified to 6i (we have to use imaginary numbers)
Answer:
You would most likely would want to use Pythagorean Theorem, witch is, a²+b²=c²
Answer:
EB=20, BC=8, AC=16
Step-by-step explanation:
The symbols indicate that:
AB=BC and AE=ED
EB and CD are parallels
AB=BC=8
AC= AB+BC
AC= 8+8
AC=16
To find EB we can use the Cosine Law
For the upper triangle x=∡EAB:
EB^2 = AB^2 + AE^2 -2*AB*AE*Cosx
AB*AE*Cosx= -(EB^2-AB^2 - AE^2)/2 (Part I)
For de big triangle:
DC^2= AC^2+AD^2 -2AC*AD*Cosx
Also:
AC=2*AB
AD=2*AE
DC^2= (2*AB)^2 + (2*AE)^2 -2(2*AB)(2*AE)*Cosx
DC^2= 4*AB^2 +4*AE^2- 8*AB*AE*Cosx
AB*AE*Cosx =-(DC^2-4*AB^2 -4*AE^2)/8 (Part II)
Part I= Part II
-(EB^2-AB^2 - AE^2)/2= -(DC^2-4*AB^2 -4*AE^2)/8
Extracting EB:
EB^2=DC^2/4
EB=DC/2
EB=40/2
EB=20
