Answer:
We can not solve for a unique cost for each soldier.
Step-by-step explanation:
Let x be the daily cost for legionaries and y be the daily cost for archers.
Upon using our given information we will get a system of linear equations as:
Now we will solve for x from our 2nd equation,
Now we will substitute this value in our 1st equation.
We can see that -3y cancels out with 3y and 9 is not equal to 10. So this is an unsolvable system. Therefore, we can not find a unique cost for each soldier.
Solutions
⇒ 5/10
5/10 is not in simplest form
1) The Greatest Common Factor of 5 and 10 is 5
5 ÷ 5 = 1
10 ÷ 5 = 2
2) simplify
5/10 in simplest form is 1/2
Answer:
The answer is below
Step-by-step explanation:
Let Q represent the amount of salt in the tank at time t.
Let's write some equations.
Mingwei's distance from Town A after
hours from 8:00 is
.
Ali's distance from Town B after
hours is
, since he doesn't start walking for 40 minutes.
When Mingwei's distance is twice Ali's, they've met up (since their distance from Town A is twice their distance from Town B).
So, this gives
, so
, so
, so the time is 10:40.
After
hours, Mingwei has traveled
kilometers while Ali has traveled sixty, so the distance between the towns is
kilometers.
Each friend receives 2 bags because 4 divided by 8 is 2
