Assuming that 10% is the probability of a switch being defective (since left-handedness has nothing to do with the problem):
For a binomial distribution, probability(r out of n) = (nCr) (p)^r (q)^(1-r)
p = 10% = 0.1, q = 1 - p = 0.9
r = 2 switches, n = total of 12 switches
probability = (12C2) (0.1)^2 (0.9)^(12-2)
probability = 66(0.1)^2 (0.9)^10
probability = 0.23
Answer:
C. 30
90/30=3
3x10= 30
SECOND PART
the second year would only have 25 acts
100/4=25
<span>A
hair stylists works ¼ to trim customer’s hair
=> 1/6 to style customer’s hair
=> 1/6 + ¼
Find the least common multiple of both denominator:
=> 1/6 + ¼ = 10/24
Simplify
=> 5/12
Now, he works 3 1/3 hour each day in 5
days
=> 3 1/3 x 5
=> 16 ½ hours in 5 days
Now, divide
=> 16 ½ divided by 5/12
=> 39 ; approximately 39 customer in 5 days can a hairstylist accommodate.</span>
The correct answer is: "(-1, -2)" .
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Note: By examining the point of intersection of the lines of the 2 graphs show in the "image attached", we can see that the point of intersection is at: "(-1, 2"); that is: "x = -1, y = 2" .
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2.2 is the answer because when you divide its a decimal
