Answer:
Find out the how much chlorine is in the pool .
To prove
As given
The amount of chlorine in a swimming pool varies directly with the volume of water.
The pool has 2.5 milligrams of chlorine per liter of water.
i.e
2.5 milligrams of chorine = 1 litre of water
There are 8000 gallons of water in the swimming pool.
As 1 gallons = 3.78541 litre (Approx)
Now convert 8000 gallons of water in litres.
8000 gallons = 8000 × 3.78541 litre
= 30283.28 litres
Now calculate chlorine in the pool for 30283.28 litres of waters.
As
2.5 milligrams of chlorine = 1 litre of water
2.5 × 30283.28 milligrams of chlorine = 30283.28 litre of water
75708.2 milligrams of chlorine for 30283.28 litre of water .
First, find the GCF. For these two numbers, it is 36. (Because 36 times 1 is 36 and 36 times 2 is 72)
Divide both sides by this, which gives you a
2:1 ratio
Answer:
B
Step-by-step explanation:
Answer:
y=5x+13
Step-by-step explanation:
when x=-3, y=-2, and when x=-2, y=3. we know that every time x increases by 1, y also increases by 5. This means that the slope is 5. to find the y-intercept, we need x to be 0. to find that, increase x by 2. if x increases by 2, then y would also increase by 10. add 10 to 3 and add 2 to -2 to get x=0 and y=13. the coordinates would be (0,13). the y-intercept is 13. now that we have enough information, we can conclude that y=5x+13. To check your answer, plug in the values for x.
Answer:
(f+g)(2) = 4
(f-g)(4) = 8
(f ÷g)(2) = 7
(f x g)(1) = 0
Step-by-step explanation:
We are given these following functions:
(f+g)(2)
At 
Then
(f+g)(2) = 4
(f-g)(4)
At x = 4
Then
(f-g)(4) = 8
(f ÷g)(2)
At x = 2
Then
(f ÷g)(2) = 7
(f x g)(1)
Then
So
(f x g)(1) = 0
