I need to solve 5 :(

Mathematics

1 answer:

GuDViN [60]2 years ago

8 0

Answer:

the distance between df is just 2dj so i belive its 12.

Step-by-step explanation:

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An air traffic controller spots two airplanes at the same altitude converging to a point as they fly at right angles to each oth

muminat

So.... notice the picture below

we know when y = 140 and x = 240, r = 250

so let's use the pythagorean theorem

$\bf r^2=x^2+y^2\implies 2r\cfrac{dr}{dt}=2x\cfrac{dx}{dt}+2y\cfrac{dy}{dt}\implies \cfrac{dr}{dt}=\cfrac{x\frac{dx}{dt}+y\frac{dy}{dt}}{r}
\\\\\\
\cfrac{dr}{dt}=\cfrac{240\cdot 480+70\cdot 140}{250}\implies \cfrac{dr}{dt}=500$

now... how much time does the controller have? well, say, plane "y" is going at dy/dt of 140mph, and is 70 miles away, 140 is 2*70, so it can cover those 70 miles in 1/2 hr, and when it does, it'll collide with the other,

so, the controller has that much, less than 1/2 hr

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3 years ago

A student has 10 coins in her pocket that have a value of $0.85. The coins are either

il63 [147K]

Answer:

$\left\{\begin{matrix}x+y=10\\ 0.05x+0.10y=0.85\end{matrix}\right.$

Step-by-step explanation:

<u>System of Equations</u>

Let's call:

x = number of nickels in the student's pocket

y = number of dimes in the student's pocket

Each nickel has a value of $0.05, so x nickels have a value of 0.05x

Each dime has a value of $0.10, so y dimes have a value of 0.10y

The student has a total of 10 coins, thus:

$x+y=10$

The total value of the coins is $0.85, thus

$0.05x+0.10y=0.85$

The system of linear equations that represents this scenario is:

$\left\{\begin{matrix}x+y=10\\ 0.05x+0.10y=0.85\end{matrix}\right.$

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3 years ago

Helena has taken out a $9,300 unsubsidized Stafford loan to pay for her college education. She plans to graduate in four years.

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The effective annual interest rate is:
i = (1 + 0.064/12)^12 - 1 = 0.066
In year 1: the interest is $613.80 (multiple $9300 by 0.066)
In year 2: the interest is $654.31 (add interest from year 1 to $9300 and multiply by 0.066)
In year 3: the interest is $656.98 (do the same as year 2)
In year 4: the interest is $657.16

The total interest is: $2582.25
The present worth of this amount is:
P = 2582.23 / (1 + 0.066)^4 = $1999.72

The answer is $1999.72.

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Answer:

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