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3 years ago

HELPPPP PLEASE!!!!!!!!!!!!!!!!!!!

Mathematics

2 answers:

gulaghasi [49]3 years ago

7 0

Answer:

Median: 5.5

Mean: 8.5

Step-by-step explanation:

Median:

3 3 8 20

3 and 8 are the two middle numbers since there can't be one.

3+8=11/2=5.5

Mean:

Add all the numbers together, and then divide by the amount of numbers there are.

3+3+8+20=34/4=8.5

Hope this helps! :) Plz mark as brainliest!!

garik1379 [7]3 years ago

6 0

Answer:

Median: 5.5 Mean: 8.5

Step-by-step explanation:

3+8+3+20=34

34/4= 8.5

3, 3, 8, 20 ((3+8)/2)

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3 years ago

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chubhunter [2.5K]

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3 years ago

7. During a sale, the price of a pair of running shoes was marked down from $89.95 to $75.00. What was the

shutvik [7]

Answer:

16.6%

Step-by-step explanation:

(75/89.95)*100=83.37....

100-83.37...=16.62...

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3 years ago

How do I solve this 4x-2y=8 y=3/2x-2

Tanya [424]

Answer:

y=1 and x= .5

Step-by-step explanation:

distribute

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4 0

3 years ago

A) Use the limit definition of derivatives to find f’(x)

Ann [662]

$\text{Given that,}\\\\f(x) = \dfrac{ 1}{3x-2}\\\\\text{First principle of derivatives,}\\\\f'(x) = \lim \limits_{h \to 0} \dfrac{f(x+h) - f(x) }{ h}\\\\\\~~~~~~~~= \lim \limits_{h \to 0} \dfrac{\tfrac{1}{3(x+h) - 2} - \tfrac 1{3x-2}}{h}\\\\\\~~~~~~~~= \lim \limits_{h \to 0} \dfrac{\tfrac{1}{3x+3h -2} - \tfrac{1}{3x-2}}{h}\\\\\\~~~~~~~~= \lim \limits_{h \to 0} \dfrac{\tfrac{3x-2-3x-3h+2}{(3x+3h-2)(3x-2)}}{h}\\\\\\$

$~~~~~~~= \lim \limits_{h \to 0} \dfrac{\tfrac{-3h}{(3x+3h-2)(3x-2)}}{h}\\\\\\~~~~~~~~= \lim \limits_{h \to 0} \dfrac{-3h}{h(3x+3h-2)(3x-2)}\\\\\\~~~~~~~~=-3 \lim \limits_{h \to 0} \dfrac{1}{(3x+3h-2)(3x-2)}\\\\\\~~~~~~~~=-3 \cdot \dfrac{1}{(3x+0-2)(3x-2)}\\\\\\~~~~~~~~=-\dfrac{3}{(3x-2)(3x-2)}\\\\\\~~~~~~~=-\dfrac{3}{(3x-2)^2}$

$\text{Given that,}~\\\\f(x) = \dfrac{1}{3x-2}\\\\\textbf{Power rule:}\\\\\dfrac{d}{dx}(x^n) = nx^{n-1}\\\\\textbf{Chain rule:}\\\\\dfrac{dy}{dx} = \dfrac{dy}{du} \cdot \dfrac{du}{dx}\\\\\text{Now,}\\\\f'(x) = \dfrac{d}{dx} f(x)\\\\\\~~~~~~~~=\dfrac{d}{dx} \left( \dfrac 1{3x-2} \right)\\\\\\~~~~~~~~=\dfrac{d}{dx} (3x-2)^{-1}\\\\\\~~~~~~~~=-(3x-2)^{-1-1} \cdot \dfrac{d}{dx}(3x-2)\\\\\\~~~~~~~~=-(3x-2)^{-2} \cdot 3\\\\\\~~~~~~~~=-\dfrac{3}{(3x-2)^2}$

8 0

2 years ago