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astraxan [27]
2 years ago
7

At a jeans factory, a random quality check found 8 pairs defective and 292 pairs with no problems. how many defective pairs can

be expected in the inventory of 3,000 pairs of jeans? 80 pairs 82 pairs 292 pairs 375 pairs
Mathematics
1 answer:
anygoal [31]2 years ago
6 0
Hello!

to solve this equation, you have to find the percentage of defects out of the total amount of jeans. if there are 300 pairs of jeans with 8 faulty pairs, then the percentage of defects would be 2.666(etc). 2.666(etc) percent of 3000 is roughly 80 pairs of defective jeans.

therefore your final answer would be 80 pairs of jeans!
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Adding these together gives

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7 (sin(19<em>x</em> + 39<em>x</em>) + sin(19<em>x</em> - 39<em>x</em>)) = 14 cos(39<em>x</em>) sin(19<em>x</em>)

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