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KiRa [710]
3 years ago
12

For what values of x will 8+x to the third power be negative

Mathematics
1 answer:
Ganezh [65]3 years ago
6 0

(8+x)^3 < 0

take the cube root

8+x <0

subtract 8

x<-8

Answer x<-8

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my 4th time another hunnid points easy right cmon now Your weclome! Cmon dont be rude i just helped you why dont you do me a fav
frosja888 [35]

Answer:

thank you sm!

Step-by-step explanation:

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6 0
2 years ago
Please help me with this sum​
Artist 52 [7]

theres a thing called a calculator

8 0
2 years ago
Read 2 more answers
1. Find the value of (−0.024)square
Lelu [443]
0.000576 is the right awnser
4 0
3 years ago
Is 4/7 greater or less than 3/5
baherus [9]
No, it is not.

4/7 ≈ 0.5714

3/5 = 0.6

Actually, 3/5 is greater than 4/7.

Another way you could do this is by multiplying 4/7 with 5/5 and by multiplying 3/5 with 7/7.

4/7 * 5/5 = 20/35

3/5 * 7/7 = 21/35

Have an awesome day! :)
6 0
2 years ago
!! AP CALCULUS AB !!<br> find the limit of [(secx*sinx) + (cscx*cosx)]/(3secx) as x approaches 3pi/2
uysha [10]

f(x)= \frac{\frac{\sin{x}}{\cos{x}}+\frac{\cos{x}}{\sin{x}}}{3\sec{x}}

\frac{\frac{\sin{x}}{\cos{x}}+\frac{\cos{x}}{\sin{x}}}{3\sec{x}} \implies \\ \frac{\sin^2{x}+\cos^2{x}}{\sin{x}\cos{x}}\frac{\cos{x}}{3}\implies \\\frac{1}{\sin{x}\cos{x}}*\frac{\cos{x}}{3}\implies \\ \frac{1}{3\sin{x}}

So,

\lim_{x \rightarrow \frac{3\pi}{2}}{f(x)=f(\frac{3\pi}{2})=\frac{1}{3\sin{\frac{3\pi}{2}}}=-\frac{1}{3}

6 0
3 years ago
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