X can be any real number
As long as it is to the power of 0, it will equal one. And because 6^0 = 1, 1^x can be any positive number, and it will still give you one.
As stated by WojtekR, even negative numbers can get 1
x = - 5
(6^0)^-5 = 1^-5 = 1/1 = 1
~ Thanks @WojtekR
Answer:
D
Step-by-step explanation:
Answer:
i think so
Step-by-step explanation:
Answer: D
Step-by-step explanation:
No such thing as a vertex of a graph... Eliminate B and C. Try f(3) = 4(3-5)(3+3) is not zero eliminate A. So answer must be D. Check: f(-3) has factor -3+3 = 0. f(5) has factor 5-5 = 0.