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2 years ago

What is the measure of ∠H? 1. 1152. 653. 504. 25

Mathematics

1 answer:

ddd [48]2 years ago

3 0

Answer:

Step-by-step explanation:

Since FG is congruent to FH, angles FGH and FHG are congruent since angles opposite congruent sides in a triangle are congruent.

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Please help!! I’m not sure how to answer this question!!

nlexa [21]

<h3>Answer: 9V</h3>

=============================================================

Reason:

The volume expression of a cone with radius r and height h is

$\frac{1}{3}\pi*r^2*h$

Let's plug in the given height h = 12 and we'd get

$\frac{1}{3}\pi*r^2*h\\\\\frac{1}{3}\pi*r^2*12\\\\\left(\frac{1}{3}*12\right)\pi*r^2\\\\4\pi*r^2\\\\$

This is the volume of the first cone. We're told the first cone has a volume of V, so we can say $V = 4\pi r^2$

We can't find the actual numeric volume because we don't know what value replaces r. So we leave it as is.

The second cone has the same height (h = 12) but the radius is now 3 times in size. Instead of r, we use 3r

Replace every copy of r with 3r. Then simplify

$4\pi*r^2\\\\4\pi*(3r)^2\\\\4\pi*9r^2\\\\9(4\pi r^2)\\\\9V\\\\$

The radius tripled which results in a volume that's 9 times bigger.

3 0

2 years ago

Type the correct answer in the box. Round your answer to the nearest integer.

umka21 [38]

Answer:

m∠ADC = 132°

Step-by-step explanation:

From the figure attached,

By applying sine rule in ΔABD,

$\frac{\text{sin}(\angle ABD)}{\text{AD}}=\frac{\text{sin}(\angle ADB)}{AB}$

$\frac{\text{sin}(120)}{35}=\frac{\text{sin}(\angle ADB)}{30}$

sin(∠ADB) = $\frac{30\text{sin}(120)}{35}$

= 0.74231

m∠ADB = $\text{sin}^{-1}(0.74231)$

= 47.92°

≈ 48°

m∠ADC + m∠ADB = 180° [Linear pair of angles]

m∠ADC + 48° = 180°

m∠ADC = 180° - 48°

m∠ADC = 132°

4 0

3 years ago

In 2010, the world's largest pumpkin weighed 1,810 kilograms. An average-sized pumpkin weighs 5,000 grams.

jekas [21]

Answer:

1,805 kg.

Step-by-step explanation:

We have been given that in 2010, the world's largest pumpkin weighed 1,810 kilograms. An average-sized pumpkin weighs 5,000 grams. We are asked to find the how much the world's largest pumpkin weighs than an average pumpkin.

First of all, we will convert the weight of average pumpkin in kilograms by dividing 5,000 by 1000 as 1 kg equals 1,000 gm.

$\text{The weight of average pumpkin}=\frac{5000\text{ gm}}{\frac{\text{1000 gm}}{\text{ 1 kg}}}$

$\text{The weight of average pumpkin}=5000\text{ gm}\times \frac{\text{ 1 kg}}{\text{1000 gm}}$

$\text{The weight of average pumpkin}=5\text{ kg}$

Now, we will subtract the weight of average pumpkin from world's largest pumpkin's weight.

$1,810\text{ kilograms}-5\text{ kilograms}=1,805\text{ kilograms}$

Therefore, the 2010 world-record pumpkin weighs 1,805 kilograms more than an average-sized pumpkin.

3 0

4 years ago

Read 2 more answers

Find the function value f (6) if f(x) = 4x-10

Olenka [21]

So first you plug 6 into the equation which is 4(6)-10.
Using PEMDAS, you solve what’s in the parenthesis first and you get 24-10.
24-10=14
f(6)=14

8 0

3 years ago

Eric and Linda are paid $41.25 for their work. Eric worked 2.5 hours, and Linda worked 3 hours. They split the money according

arsen [322]

Answer:$18.75

Step-by-step explanation:

First, find how much they get paid for working half a hour by dividing 9 from 41.25 to get 3.75.

Then, multiply 3.75 by 5 to get 18.75.

Eric's share is $18.75.

3 0

2 years ago