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3 years ago

Please help don't guess

Mathematics

2 answers:

Aloiza [94]3 years ago

5 0

Remark

I think you can only do this either as a 2 step question or as a proportion. The easiest way is the proportion.

Proportion

6 hours / 52.50 = 11/x Cross multiply

6*x = 52.50 * 11 Combine the factors on the right

6x = 577.5 Divide both sides by 6

6x/6 = 577.5/6

x = 96.25 Answer

12345 [234]3 years ago

3 0

So, just divide:

52.50 / 6 = 8.75

This means that she earns $8.75 an hour.

If this is her hourly salary, then multiply 8.75 x 11

8.75 x 11 = 96.25

So, if Paula works for 11 hours, she will earn $96.25!

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Simplify the expression to a polynomial in standard form: (3x-2)(-x^2+8x+6) (3x−2)(−x 2 +8x+6)

photoshop1234 [79]

Step-by-step explanation:

use mathaway! it helps a lot

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3 years ago

Solve (x+y) if x=-1/2 and y=-3

bixtya [17]

Answer:

$-3\frac{1}{2}$

Step-by-step explanation:

Solve

$(x+y)$

For x=-1/2 and y=-3

substitute the value of x and the value of y in the expression above

$x+y=(-\frac{1}{2})+(-3)$

Remember that

$(+1)(-1)=-1$

$x+y=-\frac{1}{2}-3=\frac{-1-6}{2}=-\frac{7}{2}$

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3 years ago

Write the equation of the line with the given slope and y-intercept. Slope = 5 y-intercept = 8 A) y=5x +8 B) x = 5y +8 C) y = 8x

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The answer is. A) y=5x+8

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3 years ago

Students in a zoology class took a final exam. They took equivalent forms of the exam at monthly intervals thereafter. After t

juin [17]

Answer:

a. 73; b. 48.9; c. 2; d. 33.8; e. 73

Step-by-step explanation:

Assume the function was

S(t)= 73 - 15 ln(t + 1), t ≥ 0

a. Average score at t = 0

S(0) = 73 - 15 ln(0 + 1) = 73 - 15 ln(1) = 73 - 15(0) =73 - 0 = 73

b. Average score at t = 4

S(4) = 73 - 15 ln(4 + 1) = 73 - 15 ln(5) = 73 - 15(1.61) =73 - 24.14 = 48.9

c. Average score at t =24

S(24) = 73 - 15 ln(24 + 1) = 73 - 15 ln(25) = 73 - 15(3.22) =73 - 48.28 = 24.7

d. Percent of answers retained

At t = 0. the students retained 73 % of the answers.

At t = 24, they retained 24.7 % of the answers.

$\text{Percent retention} = \dfrac{\text{24.7}}{\text{73}} \times 100 \, \% = \text{33.8 \%}\\\\\text{The students retained $\large \boxed{\mathbf{33.8 \, \%}}$ of their original knowledge after two years.}$

e. Maximum of the function

The maximum of the function is at t= 0.

Max = 73 %

The graph below shows your knowledge decay curve. Knowledge decays rapidly at first but slows as time goes on.

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3 years ago

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