The question here is how long does it take for a falling
person to reach the 90% of this terminal velocity. The computation is:
The terminal velocity vt fulfills v'=0. Therefore vt=g/c,
and so c=g/vt = 10/(100*1000/3600) = 36,000/100,000... /s. Incorporating the
differential equation shows that the time needed to reach velocity v is
t= ln [g / (g-c*v)] / c.
With v=.9 vt =.9 g/c,
t = ln [10] /c = 6.4 sec.
Answer:
0.675
Step-by-step explanation:
27/40
- Divide each number by 10
2.7/4
- Multiply each number by 25
67.5/100
Convert that into a decimal. :)
The solution is the interval b is in ]11.3, infinity[
Answer:
d
Step-by-step explanation:
ive had this exac problem before
