Given that the sequence is:
1,2,4,8,32
the recursive formula will be found as follows:
first term is=1
the sequence can be written as:
1,2,4,8,32
=(1*2^0),(1*2^1),(1*2^2),(1*2^3),(1*2^4)
thus the recursive formula will be
an=a1(r)^(n-1)
plugging the values we get:
an=1(2)^(n-1)
Answer:
b. the triangle is not a right triangle
Step-by-step explanation:
Vertex<em> </em>is at 
<em>y-intercept</em> is 3.
The parabola <em>opens up</em>.
Step-by-step explanation:
The graph of the equation is hereby attached in the answer area.
Vertex is the point on the parabola where the graph crosses its axis of symmetry. The axis of symmetry here(
), is shown with the dotted line in the graph attached.
<em>y-intercept </em>is defined as the value of y where the graph crosses the y-axis. In other words, when 
. Putting
And, the graph opens up as shown the graph figure as well. It is also evident from the co-efficient of 
in the given equation 
. Here, co-efficient of
So, vertex<em> </em>is at
<em>y-intercept</em> is 3.
The parabola <em>opens up</em>.
<span>Given: ΔABC
When written in the correct order, the two-column proof below describes
the statements and justifications for proving the three medians of a
triangle all intersect in one point are as follows:
Statements Justifications
Point F
is a midpoint of Line segment AB </span><span>by Construction
Point E is a midpoint of Line segment
AC
Draw Line segment BE
Draw Line segment FC
Point G is
the point of intersection between
Line segment BE and Line segment FC Intersecting Lines Postulate
Draw Line segment AG by Construction
Point D
is the point of intersection between
Line segment AG and Line segment
BC Intersecting Lines Postulate
Point H lies on Line segment AG such
that
Line segment AG ≅ Line segment GH by Construction
</span><span>Line segment FG is parallel to line segment
BH and Line
segment GE is parallel to line
segment HC Midsegment Theorem
</span><span><span>Line
segment GC is parallel to line segment
BH and Line segment BG is
parallel to
line segment HC Substitution</span>
</span>BGCH is a <span><span><span><span>Properties of a Parallelogram </span>parallelogram (opposite sides are parallel)</span>
</span>Line segment BD
≅ Line segment </span><span><span>Properties of a Parallelogram </span>DC (diagonals bisect each
other)
Line segment
AD is a median Definition of a Median</span>
Thus the most logical order of statements and justifications is: II, III, IV, I
Answer:
929,975 (C)
Step-by-step explanation:
Hope this is right. it should be cause i had to do this and i got it right
