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KIM [24]
3 years ago
10

Line j is perpendicular to the line with the given equation and the line j passes through p. write an equation of line j

Mathematics
1 answer:
Darya [45]3 years ago
8 0
Using the slope intercept formula, we can see that the slope of line p is 3/5.Since line j is perpendicular to line p it must have a slope that is the negative reciprocal(-5/3).Using the formula we can find the answer.j:y-1=-5/3(x-5)
Doing some math we get:5x+3y=28
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Answer:  2√2 - 3

Explanation:


The expession written properly is:

\frac{ \sqrt{3}- \sqrt{6}  }{ \sqrt{3}+ \sqrt{6} }

To rationalize that kind of expressions, this is to eliminate the radicals on the denominator you use conjugate rationalization.

That is, you have to multiply both numerator and denominator times the conjugate of the denominator.

The conjugate of √3+√6 is √3 - √6, so let's do it:

\frac{ \sqrt{3} - \sqrt{6} }{ \sqrt{3} + \sqrt{6} } . \frac{ \sqrt{3}- \sqrt{6}  }{ \sqrt{3}- \sqrt{6} }

To help you with the solution of that expression, I will show each part.

1) Numerator: (√3 - √6) . (√3 - √6) = (√3 - √6)^2 = (√3)^2 - 2√3√6 + (√6)^2 =

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2) Denominator: (√3 + √6).(√3 - √6) = (√3)^2 - (√6)^2 = 3 - 6 = - 3

3) Then the resulting expression is:

 9 - 6√2
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Which can be further simplified, dividing by - 3

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Answer: 2√2 - 3

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I hope this helps


4 0
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