The amount of money the person would have in 8 years s $2541.74.
<h3>How much would the person have in 8 years? </h3>
The formula for calculating future value is:
FV = P (1 + r)^nm]
Where:
FV = Future value
- P = Present value = $2000
- R = interest rate = 3% / 12 = 0.25%
- m = number of compounding = 12
- N = number of years = 8 years
Value of the account in 8 years with monthly compounding = $2000(1.0025)^(12 x 8) = $2541.74
To learn more about future value, please check: brainly.com/question/18760477
Y=-2 is a horizontal line, each point which lies on this line has the y-coordinate -2.
Only in option C both points have the y-coordinate equal to -2.
The answer is C.
Answer:

Step-by-step explanation:
we know that
The volume of a trough is equal to

where
B is the area of equilateral triangle
L is the length of a trough
step 1
Find the area of equilateral triangle B
The area of a equilateral triangle applying the law of sines is equal to

where


substitute


step 2
Find the volume of a trough

we have


substitute

