True
Lengths are preserved during a reflection, meaning it is rigid.
Hello there.
<span>How to solve 6x-3=7x-11</span>
<span><span><span>6x</span>−3</span>=<span><span>7x</span>−11</span></span>
<span><span><span><span>6x</span>−3</span>−<span>7x</span></span>=<span><span><span>7x</span>−11</span>−<span>7x</span></span></span><span><span><span>−x</span>−3</span>=<span>−11</span></span>
<span><span><span><span>−x</span>−3</span>+3</span>=<span><span>−11</span>+3</span></span><span><span>−x</span>=<span>−8</span></span>
<span><span><span>−x/</span><span>−1</span></span>=<span><span>−8/</span><span>−1</span></span></span><span>x=8</span>
Answer: 8
Answer:
0.30
Step-by-step explanation:
P(x ≤ -3) = P(x=-3) + P(x=-5)
P(x ≤ -3) = 0.13 + 0.17
P(x ≤ -3) = 0.30
Answer:
i dont understand please exsplain more
Step-by-step explanation:
Answer:
37 degrees
Step-by-step explanation:
1. m∠CBA = 71+45 = 116 degrees
2. m∠CBA = m∠CDA because of the quadrilateral property of opposite sides.
3. m∠CBA + m∠CDA = 2*116 = 232.
4. Total angle measure of a quadrilateral is 360 degrees, so m∠BAD + m∠BCD = 360-232 = 128 degrees.
5. m∠BAD = m∠BCD = 128/2 = 64 degrees
6. m∠BAC = m∠BAD - m∠CAD = 64 - 27 = 37 degrees