Answer:
Amount = p( 1+r/100) ^n
= 12000 ( 1+10/100) ²
= 12000( 10/10+1/10) ²
= 12000( 11/10) ²
= 12000 x 11/10 x 11/10
= 14520 rs.
Compund interest = amount - principal
= 14520 - 12000
= 2520rs.
Next question :- no of men can complete a piece of work in 7 days = 36
No of men can complete a piece of work in 42 day = ( 36 x 7 ) ÷ 42
= 252 ÷ 42
= 6 men
Answer:
Part 1) see the procedure
Part 2) 
Part 3) 
Part 4) The minimum number of months, that he needs to keep the website for site A to be less expensive than site B is 10 months
Step-by-step explanation:
Part 1) Define a variable for the situation.
Let
x ------> the number of months
y ----> the total cost monthly for website hosting
Part 2) Write an inequality that represents the situation.
we know that
Site A

Site B

The inequality that represent this situation is

Part 3) Solve the inequality to find out how many months he needs to keep the website for Site A to be less expensive than Site B

Subtract 4.95x both sides


Divide by 5 both sides


Rewrite

Part 4) describe how many months he needs to keep the website for Site A to be less expensive than Site B.
The minimum number of months, that he needs to keep the website for site A to be less expensive than site B is 10 months
Answer:
a. 20h + 8
Step-by-step explanation:
-2(-7h-4) + 6h = 14h + 8 + 6h = 20h + 8