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3 years ago

Which line has an equation of y=-5x+4 in slope-intercept form?

2 answers:

4 0

You can figure the line for each pair of points, or you can try the points in the equation you have and see which are on the line.

First answer: x=1, y=-5×1 +4 = -1 . . . not 9. (1, 9) is not a point on the line

Second answer: x=2, y=-5×2 +4 = -6 . . . not -14. (2, 14) is not a point on the line

Third answer: (see the calculation for the first answer) . . . -1 ≠ 1. (1, 1) is not a point on the line

Fourth answer: (see the calculation for the second answer) We know that (2, -6) is on the given line. Checking (4, -16), we find it is as well.

The appropriate choice is the 4th answer:

... a line passing through the points (2, -6) and (4, -16)

Phoenix [80]3 years ago

4 0

Answer: answer is D

Step-by-step explanation:

I TOOK THE TEST

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3 years ago

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Serga [27]

Answer:

(d) $\displaystyle 12x^3 - 15x^2 + 2$

General Formulas and Concepts:

Algebra I

Functions
Function Notation

Calculus

Derivatives

Derivative Notation

Derivative Property [Addition/Subtraction]: $\displaystyle \frac{d}{dx}[f(x) + g(x)] = \frac{d}{dx}[f(x)] + \frac{d}{dx}[g(x)]$

Basic Power Rule:

f(x) = cxⁿ
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Step-by-step explanation:

Step 1: Define

Identify

$\displaystyle y = 3x^4 - 5x^3 + 2x - 1$

Step 2: Differentiate

Basic Power Rule: $\displaystyle y' = 4(3x^{4 - 1}) - 3(5x^{3 - 1}) + 2x^{1 - 1} - 0$
Simplify: $\displaystyle y' = 4(3x^3) - 3(5x^2) + 2$
Multiply: $\displaystyle y' = 12x^3 - 15x^2 + 2$

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Derivatives

Book: College Calculus 10e

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