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MAXImum [283]
3 years ago
14

Angles and transversals thank you

Mathematics
1 answer:
faltersainse [42]3 years ago
7 0

Answer:

#11-13: 118 , 97 , 62

#7-10: 92 , 125 , 56 , 130

Step-by-step explanation:

#11. Supplementary angles (A + B = 180)

  • (n + 7) + (3n - 47) = 180
  • n = 55
  • <ABC = 3(55) - 47 = 118 degrees

#12. Supplementary angles

  • 83 + x = 180
  • x = 97
  • <ABC = 97 degrees

#13. Congruent angles (A = B)

  • (8x - 34) = (5x +2)
  • x = 12
  • <DEF = 5 (12) + 2 = 62 degrees

#7. Congruent angles

  • (3x +23) = 4x
  • x = 23
  • <ABC = 4(23) = 92 degrees

#8. Congruent angles

  • 5x = (3x + 50)
  • x = 25
  • <MPQ = 3(25) + 50 = 125 degrees

#9. Congruent angles

  • (a + 28) = 2a
  • a = 28
  • <MNP = (28) + 28 = 56 degrees

#10. Congruent angles

  • 5y = (2y + 78)
  • y = 26
  • <WXZ = 5(26) = 130 degrees

I hope this helps!

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PLEASE HELP!!! I JUST NEED A STEP-BY-STEP!!!!!!
Naya [18.7K]

Answer:

Step-by-step explanation:

=5\displaystyle\int_{0}^{\pi/6}dx\displaystyle\int_{0}^{2}x\sec^2(xy)dy\\=5\displaystyle\int_{0}^{\pi/6}dx\displaystyle\int_{0}^{2}\sec^2(xy)d(xy)\\=5\displaystyle\int_{0}^{\pi/6}dx\tan(xy)|_{y=0}^{y=2}

=5\displaystyle\int_{0}^{\pi/6}\tan(2x)dx\\=-\frac{5}{2}\ln\cos(2x)|_{0}^{\pi/6}\\=-\frac{5}{2}[\ln\cos(\pi/3) - \ln\cos(0)]\\

=-\frac{5}{2}\ln{\frac{1}{2}

6 0
2 years ago
The lines given by the equations y=4x and y=0.25x are
d1i1m1o1n [39]

They are not parallel because the slopes are different (slope of 4 and slope of 0.25)

Neither are they perpendicular. If they were then m1*m2  ( the product of their slopes) would be -1 ). The product of these slopes = 4*0.25 = 1)

So choice  A is the correct one.


6 0
3 years ago
Multiply by 4, then divide by 2 First term: 60 ​
harina [27]

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3 0
3 years ago
Rewrite the fraction with the denominator of 33 6/11=/33
Sonja [21]
You would time the denominator by 3 so 11*3 would be 33 then times the numerator by the same so 6*3 soot would be 18/33
7 0
3 years ago
Solve the system by elimination.(show your work)
PilotLPTM [1.2K]

Answer:

x = 1 , y = 1 , z = 0

Step-by-step explanation by elimination:

Solve the following system:

{-2 x + 2 y + 3 z = 0 | (equation 1)

-2 x - y + z = -3 | (equation 2)

2 x + 3 y + 3 z = 5 | (equation 3)

Subtract equation 1 from equation 2:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x - 3 y - 2 z = -3 | (equation 2)

2 x + 3 y + 3 z = 5 | (equation 3)

Multiply equation 2 by -1:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+3 y + 2 z = 3 | (equation 2)

2 x + 3 y + 3 z = 5 | (equation 3)

Add equation 1 to equation 3:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+3 y + 2 z = 3 | (equation 2)

0 x+5 y + 6 z = 5 | (equation 3)

Swap equation 2 with equation 3:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+5 y + 6 z = 5 | (equation 2)

0 x+3 y + 2 z = 3 | (equation 3)

Subtract 3/5 × (equation 2) from equation 3:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+5 y + 6 z = 5 | (equation 2)

0 x+0 y - (8 z)/5 = 0 | (equation 3)

Multiply equation 3 by 5/8:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+5 y + 6 z = 5 | (equation 2)

0 x+0 y - z = 0 | (equation 3)

Multiply equation 3 by -1:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+5 y + 6 z = 5 | (equation 2)

0 x+0 y+z = 0 | (equation 3)

Subtract 6 × (equation 3) from equation 2:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+5 y+0 z = 5 | (equation 2)

0 x+0 y+z = 0 | (equation 3)

Divide equation 2 by 5:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+y+0 z = 1 | (equation 2)

0 x+0 y+z = 0 | (equation 3)

Subtract 2 × (equation 2) from equation 1:

{-(2 x) + 0 y+3 z = -2 | (equation 1)

0 x+y+0 z = 1 | (equation 2)

0 x+0 y+z = 0 | (equation 3)

Subtract 3 × (equation 3) from equation 1:

{-(2 x)+0 y+0 z = -2 | (equation 1)

0 x+y+0 z = 1 | (equation 2)

0 x+0 y+z = 0 | (equation 3)

Divide equation 1 by -2:

{x+0 y+0 z = 1 | (equation 1)

0 x+y+0 z = 1 | (equation 2)

0 x+0 y+z = 0 | (equation 3)

Collect results:

Answer: {x = 1 , y = 1 , z = 0

6 0
3 years ago
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