Answer:

General Formulas and Concepts:
<u>Calculus</u>
Differentiation
- Derivatives
- Derivative Notation
Derivative Property [Multiplied Constant]:

Derivative Property [Addition/Subtraction]:

Derivative Rule [Basic Power Rule]:
- f(x) = cxⁿ
- f’(x) = c·nxⁿ⁻¹
Integration
Integration Rule [Reverse Power Rule]:

Integration Property [Multiplied Constant]:

Integration Methods: U-Substitution and U-Solve
Step-by-step explanation:
<u>Step 1: Define</u>
<em>Identify given.</em>
<em />
<u>Step 2: Integrate Pt. 1</u>
<em>Identify variables for u-substitution/u-solve</em>.
- Set <em>u</em>:

- [<em>u</em>] Differentiate [Derivative Rules and Properties]:

- [<em>du</em>] Rewrite [U-Solve]:

<u>Step 3: Integrate Pt. 2</u>
- [Integral] Apply U-Solve:

- [Integrand] Simplify:

- [Integral] Rewrite [Integration Property - Multiplied Constant]:

- [Integral] Apply Integration Rule [Reverse Power Rule]:

- [<em>u</em>] Back-substitute:

∴ we have used u-solve (u-substitution) to <em>find</em> the indefinite integral.
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Topic: AP Calculus AB/BC (Calculus I/I + II)
Unit: Integration
This is the product of the square of a binomial expression. Therefore, it will have two factors.
Square of a binomial: a² + 2ab + b² = (a+b)²
The process:
9x² + 24x + 16
= (3x)² +2(3x)(4) + (4)²
= (3x + 4)² or (3x+4)(3x+4)
I hope this helps :)
Answer:28.8 ounces
Step-by-step explanation:20% -36 =22.8
Answer:
1
Step-by-step explanation:
When turning remainders into mixed numbers remember Place the remainder as the numerator, or the top number, in your fraction. Put the divisor on the bottom of the fraction, or the denominator.
Proceed to check your work :)
hope this helps
9514 1404 393
Answer:
23, 49
Step-by-step explanation:
Let s represent the smaller of the two numbers. Then the larger is s+26, and the sum is ...
s + (s+26) = 72
2s = 72 -26
s = (72 -26)/2 = 23
Then the larger number is
s +26 = 49
The two numbers are 23 and 49.
_____
The reason we wrote the solution this way is to show you that the smaller number is half the difference between the given sum (72) and difference (26). This is the generic solution to a "sum and difference" problem. The smaller number is always half the difference of the give sum and difference. (Similarly, the larger is always half the sum of the given sum and difference.)
That is, the two numbers are always half the sum ± half the difference:
72/2 ± 26/2 = {36+13, 36-13} = {49, 23}