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vivado [14]
3 years ago
15

What are the possible values of x and y for two distinct points, (5, –2) and (x, y), to represent a function?

Mathematics
2 answers:
bonufazy [111]3 years ago
8 0

The <em><u>correct answer</u></em> is:

Any real number for x except 5, and any real number for y.

Explanation:

A function is a relation in which each element of the domain, or x-value, is mapped to one element of the range, or y-value.  This means that no x can be mapped to more than one y, so if we have the same number used twice for x, we do not have a function.

This means that 5 cannot be used for x in the other ordered pair.

Since there is no restriction on y in order to be a function, y can be any real number.

lawyer [7]3 years ago
5 0
Any real number except 5 for the x vale and for y value is any real number 

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Answer:

12(9+7)

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The five circles making up this archery target have diameters of length $2,4,6,8,$ and $10$. What is the total red area?
Sliva [168]

Answer:

A=15\pi\ units^2

Step-by-step explanation:

<u><em>The picture of the question in the attached figure</em></u>

we know that

It is given that the diameter of 5 circles making up the archery is 2,4,6,8, and 10.

To determine the total red area, we use the formula for area of the circle

A=\pi r^{2}

step 1

Find the Area of the 1st red circle

r=2/2=1\ unit ---> the radius is half the diameter

A_1=\pi (1)^{2}=\pi\ units^2

step 2

Find the Area of the 2nd white circle

r=4/2=2\ units ---> the radius is half the diameter

A_2=\pi (2)^{2}=4\pi\ units^2

step 3

Find the Area of the 3rd red circle

r=6/2=3\ units ---> the radius is half the diameter

A_3=\pi (3)^{2}=9\pi\ units^2

step 4

Find the Area of the 4th white circle

r=8/2=4\ units ---> the radius is half the diameter

A_4=\pi (4)^{2}=16\pi\ units^2

step 5

Find the Area of the 5th red circle

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A_5=\pi (5)^{2}=25\pi\ units^2

The total red area is given by

A=A_5-A_4+A_3-A_2+A_1

substitute

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