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RoseWind [281]
2 years ago
11

Find the area if the pentagon. I’ll mark the brainiest :)

Mathematics
1 answer:
Keith_Richards [23]2 years ago
7 0

Answer:

688.19 inches

Step-by-step explanation:

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WILL GIVE BRAINLYIST
marysya [2.9K]

Answer:

64 degrees

Step-by-step explanation:

Since the triangles are similar they have the same angle measures

\frac{PR}{PQ} =\frac{SU}{ST}          \frac{21}{14}= \frac{6}{4}

∠P = ∠S ∠R =∠U ∠Q=∠T

We know 2 of the angle measures: ∠S and ∠R, and since they are similar we know ∠P and ∠U

In triangles the sum of all angle measures is always 180 degrees, so we can solve for ∠Q with this formula

A+B+C=180

46+70+C+180

116+C=180

subtract 116 from both sides

C=64

Therefore ∠Q is equal to 64 degrees

3 0
3 years ago
Find - 2 2/6 + (5/6)
Bad White [126]

Answer:-3/2

Step-by-step explanation:

-2 2/6+5/6

-7/3 + 5/6

(2x-7+1x5) ➗ 6

(-14+5) ➗ 6

-9 ➗ 6

-9/6=-3/2

5 0
3 years ago
Angelique says that finding the absolute value of a number is the same as finding the opposite of the number. For example |-5|=5
jarptica [38.1K]

If u r trying 2 find the absolute value of a positive number, the absolute value of it will not be a negative, it will always be a positive.
8 0
3 years ago
Read 2 more answers
The height of a right cylinder is 6r, where r is the radius. Write a function f in simplest form that represents the ratio of th
finlep [7]
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4 0
2 years ago
Ken started a savings account for school. He plans on spending 10% of the money he earns for leisure activities. He needs to hav
uranmaximum [27]

Answer:

$2,400

Step-by-step explanation:

Ken intends to start a savings account

10% = leisure spending

This means 90% = Expenses for school

Let us represent the amount he must save as : x

Hence in other for him to have $2,160 in his savings account, the amount Ken must earn is calculated as:

90/100 × x = $2,160

Cross Multiply

90x = $2,160 × 100

x = ($2,160 × 100) ÷ 90

x =$2,400

Therefore, the amount Ken has to earn to have the amount needed for school is $2,400

5 0
3 years ago
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