Question

Determine the solution to the system of equations below.

Answer 1

Answer:

$\boxed{\sf{x=7 \quad y=2}}$

Step-by-step explanation:

To solve this problem, isolate it on one side of the equation.

x-3y=1 and 3x-5y=11

x-3y=1: x=1+3y

x=1+3y

Substitute.

x=1+3y= 3(1+3y)-5y=11

Solve.

3+4y=11

Subtract by 3 from both sides.

3+4y-3=11-3

Solve.

11-3=8

Rewrite the problem down.

4y=8

Divide by 4 from both sides.

4y/4=8/4

Solve.

8/4=2

y=2

x=1+3y

x=1+3*2

Solve.

PEMDAS stands for:

• Parenthesis
• Exponents
• Multiply
• Divide
• Add
• Subtract

1+3*2

Multiply.

3*2=6

Add.

1+6=7

x=7

• Therefore, the correct answer is x=7 and y=2.

I hope this helps you! Let me know if my answer is wrong or not.