Question

Can someone solve this question to me.i will mark brainliest. :)

Answer 1

Answer:

• Parent Function:  $y=\sqrt{x}$
• Horizontal shift: right 3 units
• Vertical shift: up 3 units
• Reflection about the x-axis: none
• Vertical strech: streched

Step-by-step explanation:

assume that $y=\sqrt{x}$ is $f(x)=\sqrt{x}$ and $y=\sqrt{-2x+6}+3$ is

$g(x)=\sqrt{-2x+6}+3\\ f(x)=\sqrt{x} \\g(x)=\sqrt{-2x+6}+3$

The transformation from the first equation to the second equation can be found by finding a,h and k for each equation.

$y=a\sqrt{x-h}+k$

factor a 1 out of the absolute value to make the coefficient of x equal to 1

$y=\sqrt{x}$

factor a 2 out of the absolute value to make the coefficient of x equal to 1

$y=\sqrt{2}\sqrt{x-3}+3$

find a, h and k for $y=\sqrt{2}\sqrt{x-3}+3$

$a=1.41421356\\ h=3\\k=3$

the horizontal shift depends on the value of h when $h > 0$, the horizontal shift is described as:

$g(x)=f(x+h)$ - the graph is shifted to the left h units

$g(x)=f(x-h)$ - the graph is shifted to the right h units

the vertical shift depends on the value of k