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2 years ago

Someone please please help me

Mathematics

1 answer:

nlexa [21]2 years ago

3 0

Answer:

Step-by-step explanation:

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In the given diagram , TY is a tangent to the circle TVS . If <SVT = 48° and |VS| = |ST| . What is < VTY.

ycow [4]

Answer:

84°

Step-by-step explanation:

∠VTY is the tangent chord angle

Tangent chord angle is the half of the intercepted arc

∠TSV is the inscribed angle.

Inscribed angle is the half of the intercepted arc

Since both of the mentioned angles refer to same arc, they are of same value.

∠VTY = ∠TSV

ΔTVS is isosceles as VS = ST, therefore the opposite angles are same.

m∠T = m∠V = 48°

The measure of angle S

m∠S = 180° - 2*48° = 84°

The required angle

m∠VTY = 84°

4 0

3 years ago

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Write an expression in expanded form that is equivalent to 3(7d + 4e)

Vladimir79 [104]

21d+12e
answer mine pleadw

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3 years ago

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What is the simplified form of the expression? 7r - 8r + 13 -2r + 5? Please help me

ArbitrLikvidat [17]

Answer:

- 3r + 18

Step-by-step explanation:

7r - 8r - 2r + 13 + 5 = 7r - 10r + 18

6 0

3 years ago

Plz plz plz help fast it’s graded

Paraphin [41]

Answer: 117 degrees

Step-by-step explanation:

8 0

3 years ago

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Write an equation for the circle with endpoints of a diameter (9, 4) and (-3, -2)

inysia [295]

If the diameter is at (9,4) and (-3,-2), then the center of the circle is the midpoint of that segment.

and since we know that the radius of a circle is half of the diameter, whatever long that diameter segment is, the radius is half that.

$\bf ~~~~~~~~~~~~\textit{middle point of 2 points }
\\\\
\begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
% (a,b)
&&(~ 9 &,& 4~) 
% (c,d)
&&(~ -3 &,& -2~)
\end{array}\qquad
% coordinates of midpoint 
\left(\cfrac{ x_2 + x_1}{2}\quad ,\quad \cfrac{ y_2 + y_1}{2} \right)
\\\\\\
\left( \cfrac{-3+9}{2}~~,~~\cfrac{-2+4}{2} \right)\implies \stackrel{center}{(3~,~1)}$

$\bf -------------------------------\\\\
~~~~~~~~~~~~\textit{distance between 2 points}
\\\\
\begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
% (a,b)
&&(~ 9 &,& 4~) 
% (c,d)
&&(~ -3 &,& -2~)
\end{array}
\\\\\\
d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}
\\\\\\
d=\sqrt{(-3-9)^2+(-2-4)^2}\implies d=\sqrt{(-12)^2+(-6)^2}
\\\\\\
d=\sqrt{180}\qquad \qquad \qquad radius=\cfrac{\sqrt{180}}{2}$

$\bf -------------------------------\\\\
\textit{equation of a circle}\\\\ 
(x- h)^2+(y- k)^2= r^2
\qquad 
center~~(\stackrel{3}{ h},\stackrel{1}{ k})\qquad \qquad 
radius=\stackrel{\frac{\sqrt{180}}{2}}{ r}
\\\\\\
(x-3)^2+(y-1)^2=\left( \frac{\sqrt{180}}{2} \right)^2\implies (x-3)^2+(y-1)^2=\cfrac{(\sqrt{180})^2}{2^2}
\\\\\\
(x-3)^2+(y-1)^2=\cfrac{180}{4}\implies (x-3)^2+(y-1)^2=45$

7 0

3 years ago