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kifflom [539]
2 years ago
6

Help picture below problem 15

Mathematics
1 answer:
nikitadnepr [17]2 years ago
3 0

Answer:

Supplementary

Step-by-step explanation:

The two angles are completely different from each other and if you combine them together it'll form a straight line making it 180 degrees

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This will be the last prob for today but thx soo much for helping​
____ [38]

Answer:

Step-by-step explanation:

If you simplify you get 0 = 19/3, which is false. So there is no solution.

8 0
3 years ago
I will give brainliest to the correct answer!
Viefleur [7K]

Answer:

 c). 2x^3  x  ^3\sqrt{4}

Step-by-step explanation:

i hope this is correct! have a good day! c:

6 0
2 years ago
What are the answers to the last two questions?
irga5000 [103]

Answer:

(-1)(x+3)(x-2)

Step-by-step explanation:

<u>Factoring</u>

We are given a trinomial:

-x^2-x+6

The following steps are done to factor the trinomial.

1. Confirm there are no common factors: No common factors (given)

2. Factor out -1:

Multiply all the terms by -1 and take -1 out:

\boxed{(-1)(x^2+x-6)}

3. Factor

x^2+x-6 = (x+p)(x+q)

We have to find two numbers p and q whose product is -6 and the sum is 1. Those numbers are 3 and -2 (in any order):

Factoring:

x^2+x-6 = (x+3)(x-2)

The final factoring is:

\boxed{(-1)(x+3)(x-2)}

3 0
3 years ago
Another 100 pt question, so whoever wants it, please help answering both parts of the question.
Crank

Answer:

11. \displaystyle 60° = m∠REN

10. \displaystyle 60° = m∠ENR

Step-by-step explanation:

In every rectangle, when you have two diagonal segment bisectors, you will always have a circumcentre showing all midpoints of both segment bisectors, however, it measures 120° going <em>vertical</em> and 60° going <em>horisontal</em>, so with that being said, you have your answers.

I am joyous to assist you anytime.

* NOTE: Remember, the sum of the interior angles of ALL TRIANGLES is 180°.

6 0
3 years ago
Read 2 more answers
I need help with 7 8 and 9 question perimeter and area
strojnjashka [21]

The perimeter and area of the equilateral, isosceles and right angled triangle are  16.2mm 12.6mm², 15.2in and 9.61in², 21.47yds and 16.81yds² respectively.

<h3>What is the area of the equilateral, isosceles and right angle triangle?</h3>

Note that:

The perimeter of an Equilateral triangle is expressed as P = 3a

The area of an Equilateral triangle is expressed as A = ((√3)/4)a²

Where a is the dimension of the side.

The perimeter of an Isosceles triangle is expressed as P = 2a + b

The area of an Isosceles triangle is expressed as A = (ah)/2

Where b is the slant height, a is the dimension of the base and h is the height.

The perimeter of a Right angled triangle is expressed as P = a + b + c

The area of a Right angled triangle is expressed as A = (ab)/2

Where a and b is the dimension of the two sides other than the hypotenuse and c is the hypotenuse.

For the Equilateral triangle.

Given that;

  • a = 5.4mm
  • Perimeter P = ?
  • Area A = ?

Perimeter P = 3a

P = 3 × 5.4mm

P = 16.2mm

Area A = ((√3)/4)(5.4mm)²

A = ((√3)/4)( 29.16mm² )

A = 12.6mm²

The Perimeter and Area of the Equilateral triangle are 16.2mm 12.6mm² respectively.

For the Isosceles triangle.

Given that;

  • Base a = 3.4in
  • Slant height b = 5.9in
  • Perimeter P = ?
  • height h = ?
  • Area A = ?

Perimeter P = 2a + b

P = 2(b) + a

P = 2(5.9in) + 3.4in

P = 11.8in + 3.4in

P = 15.2in

The height h is the imaginary line drawn upward from the center of a.

First, we calculate the height using Pythagorean theorem

x² = y² + z²

Where x = b = 5.9in, y = a/2 = 3.4in/2 = 1.7in, and z = h

(5.9in)² = (1.7in)² + h²

34.81in² = 2.89in² + h²

h² = 34.81in² - 2.89in²

h² = 31.92in²

h = √31.92in²

h = 5.65in

Now, the area will be;

A = (ah)/2

A = (3.4in × 5.65in )/2

A = 19.21in²/2

A = 9.61in²

The Perimeter and Area of the Isosceles triangle are 15.2in and 9.61in² respectively.

For the Right angled triangle.

Given that;

  • a = 8.2yds
  • b = 4.1yds
  • c = 9.17yds
  • Perimeter P = ?
  • Area A = ?

Perimeter P = a + b + c

P = 8.2yds + 4.1yds + 9.17yds

P = 21.47yds

Area A = (ab)/2

A = ( 8.2yds × 4.1yds)/2

A = ( 33.62yds²)/2

A = 16.81yds²

The Perimeter and Area of the Right angled triangle are 21.47yds and 16.81yds² respectively.

Therefore, the perimeter and area of the equilateral, isosceles and right angled triangle are  16.2mm 12.6mm², 15.2in and 9.61in², 21.47yds and 16.81yds² respectively.

Learn more about Pythagorean theorem here: brainly.com/question/343682

#SPJ1

3 0
1 year ago
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