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2 years ago

Find the value of the expression.

Mathematics

1 answer:

Olegator [25]2 years ago

5 0

$( (\frac{3}{5}) {}^{0} ) {}^{ - 2} = (1) {}^{ - 2} = \frac{1}{1 {}^{2} } = \frac{1}{1} = 1$

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In one hour, 17 cars drive through an intersection. Two-fifths of the 17 cars fail to come to a complete stop at the stop sign.

Rasek [7]

Answer:

Step-by-step explanation:

When you have a number (17) and want to know some fraction (2/5) of that number, you should multiply the number by the fraction.

17 * (2/5)

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3 years ago

Which ordered pair is a solution of the equation?<br> y = -6x+1

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Question 3: Which of the following constructions would help to construct a line passing through point C that is perpendicular to

lakkis [162]

Answer:

Construction of a perpendicular bisector through C

Step-by-step explanation:

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2 years ago

A vertical cylinder is leaking water at a rate of 4m3/sec. If the cylinder has a height of 10m and a radius of 2m, at what rate

Lyrx [107]

Answer:

Therefore the rate change of height is $\frac{1}{\pi}$ m/s.

Step-by-step explanation:

Given that a vertical cylinder is leaking water at rate of 4 m³/s.

It means the rate change of volume is 4 m³/s.

$\frac{dV}{dt}=4 \ m^3/s$

The radius of the cylinder remains constant with respect to time, but the height of the water label changes with respect to time.

The height of the cylinder be h(say).

The volume of a cylinder is $V=\pi r^2 h$

$=( \pi \times 2^2\times h)\ m^3$

$\therefore V= 4\pi h$

Differentiating with respect to t.

$\frac{dV}{dt}=4\pi \frac{dh}{dt}$

Putting the value $\frac{dV}{dt}$

$\Rightarrow 4\pi \frac{dh}{dt}=4$

$\Rightarrow \frac{dh}{dt}=\frac{4}{4\pi}$

$\Rightarrow \frac{dh}{dt}=\frac{1}{\pi}$

The rate change of height does not depend on the height.

Therefore the rate change of height is $\frac{1}{\pi}$ m/s.

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2 years ago