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2 years ago

Find the value of the expression.

Mathematics

1 answer:

Olegator [25]2 years ago

5 0

$( (\frac{3}{5}) {}^{0} ) {}^{ - 2} = (1) {}^{ - 2} = \frac{1}{1 {}^{2} } = \frac{1}{1} = 1$

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A recipe calls for 9 1/2 cups of flour to make a batch of cookies. How many batches of cookies can be made if you have 38 cups o

Fiesta28 [93]

Answer : 4

Explanation:

9 1/2 cups of flour makes 1 batch of cookies so make that into a decimal: 9.5

and take 38 divided by 9.5 and you get your answer.

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3 years ago

144 ft squared to square yards?

Iteru [2.4K]

144 feet is 16 yards^2

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3 years ago

Help me please giving more than 5 points!

Scilla [17]

To find the median you need to lay out all the answers by lowest to highest. Then, you’ll need to find the number that’s in the middle and that’s the median. However, if there’s 2 middle numbers you’ll need to add them then divide it by 2 and that’s the median.

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3 years ago

Read 2 more answers

Suppose the sediment density (g/cm) of a randomly selected specimen from a certain region is normally distributed with mean 2.65

erma4kov [3.2K]

Answer:

Probability that the sample average is at most 3.00 = 0.98030

Probability that the sample average is between 2.65 and 3.00 = 0.4803

Step-by-step explanation:

We are given that the sediment density (g/cm) of a randomly selected specimen from a certain region is normally distributed with mean 2.65 and standard deviation 0.85.

Also, a random sample of 25 specimens is selected.

Let X bar = Sample average sediment density

The z score probability distribution for sample average is given by;

Z = $\frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\mu$ = population mean = 2.65

$\sigma$ = standard deviation = 0.85

n = sample size = 25

(a) Probability that the sample average sediment density is at most 3.00 is given by = P( X bar <= 3.00)

P(X bar <= 3) = P( $\frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } }$ <= $\frac{3-2.65}{\frac{0.85}{\sqrt{25} } }$ ) = P(Z <= 2.06) = 0.98030

(b) Probability that sample average sediment density is between 2.65 and 3.00 is given by = P(2.65 < X bar < 3.00) = P(X bar < 3) - P(X bar <= 2.65)

P(X bar < 3) = P( $\frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } }$ < $\frac{3-2.65}{\frac{0.85}{\sqrt{25} } }$ ) = P(Z < 2.06) = 0.98030

P(X bar <= 2.65) = P( $\frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } }$ <= $\frac{2.65-2.65}{\frac{0.85}{\sqrt{25} } }$ ) = P(Z <= 0) = 0.5

Therefore, P(2.65 < X bar < 3) = 0.98030 - 0.5 = 0.4803 .

8 0

3 years ago

Simplify 5+10−2^3 <br> thanks in advance

andrey2020 [161]

5+10-2^3
= 7

Step by step:
5+10-2^3
= 15 - 2^3
= 15 - 8
= 7

8 0

3 years ago