Question

Can any one help please :)

Answer 1

Answer:

B

Step-by-step explanation:

First, subtract 3 by the numbers

-8 > 4x > 4

Remember to flip the inequality signs

Second, divide all the numbers by 4

-2 < x < 1

Flip the inequality signs again

-2 > x > 1

I am not very experienced with these problems so I might be wrong.

Answer 2

Answer:

B: x > -2 and x ≤ 1

Step-by-step explanation:

–5 < 4x + 3 ≤ 7  

Since -5 is less than 4x + 3, and 4x + 3 is greater than or equal to 7:  

We can solve the given inequality as –5 < 4x + 3 and 4x + 3 ≤ 7 to find the possible intervals for x:

Let's start with –5 < 4x + 3 by switching or rewriting the inequality statement as:  

4x + 3 > –5  

Then, we can subtract 3 from both sides of the inequality to isolate 4x:  

4x + 3 – 3 > –5 – 3

4x > – 8  

Divide both sides of the inequality by 4:  

$\frac{4x}{4} > \frac{-8}{4}$

x > –2

Next, we can work on 4x + 3 ≤ 7:

4x + 3 ≤ 7

Subtract 3 from both sides of the inequality:

4x + 3 – 3 ≤ 7 – 3

4x ≤ 4

Divide both sides of the inequality by 4 to solve for x:  

$\frac{4x}{4} \leq \frac{4}{4}$  

x ≤ 1

So, the answer is  OPTION B:  x > -2 and x ≤ 1